
Write the names of reagents and equations for the preparation of the following ethers by Williamson’s synthesis.
A.1-propoxypropane
B.Ethoxy benzene
C.2-methoxy-2-methyl propane
D.1-methoxy ethane
Answer
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Hint: Williamson synthesis is the general method for the synthesis of ether. It involves the nucleophilic displacement of a halide ion or other leaving group by an alkoxide ion. To solve this question, we need to know the reaction mechanism of Williamson synthesis.
Complete step by step answer:
Basically, the name of this reaction was coined after the scientist named Alexander William Williamson. It is a reaction that uses deprotonated alcohol and an organohalide to form an ether. In this reaction, the nucleophile attacks the alkyl halide and forms an ether from the back. This response takes place in the single step, which is both cleavage and bond formation. The products are then formed by elimination. The general reaction is as shown:
$RX + R'ONa \to R - O - R' + NaX$
Now, let’s discuss the name of reagents and their respective equations for the preparation of ethers by Williamson’s synthesis.
1)1-propoxypropane- It is formed by the reaction of sodium prop oxide and 1-bromopropane. The reaction is as shown:
$C{H_3}C{H_2}CHONa + C{H_3}C{H_2}C{H_2}Br \to {C_2}{H_5}C{H_2} - O - C{H_2}{C_2}{H_5} + NaBr$
2)Sodium phenoxide and bromoethane react to give ethoxy benzene. The reaction is as shown:
3)In the third case, the reactants are sodium-2-methyl 2 prop oxide and bromoethane and the product obtained is 2-methoxy- 2-methylpropane. The reaction is as shown:
4)In the last case, sodium ethoxide and bromoethane react together to form 1-methoxyethane. The reaction is as shown:
$C{H_3}C{H_2} - ONa + C{H_3} - Br \to C{H_3}C{H_2} - O - C{H_3} + NaBr$
Note: There are few limitations of Williamson’s synthesis reaction. The tertiary alkyl halides or primary or secondary alkyl halides that are sterically impeded continue to undergo ${E_2}$ removal in the presence of alkoxide, which serves as a base in addition to being a nucleophile. Moreover, this reaction is significant in the organic chemistry history as it has helped to prove the ether structures.
Complete step by step answer:
Basically, the name of this reaction was coined after the scientist named Alexander William Williamson. It is a reaction that uses deprotonated alcohol and an organohalide to form an ether. In this reaction, the nucleophile attacks the alkyl halide and forms an ether from the back. This response takes place in the single step, which is both cleavage and bond formation. The products are then formed by elimination. The general reaction is as shown:
$RX + R'ONa \to R - O - R' + NaX$
Now, let’s discuss the name of reagents and their respective equations for the preparation of ethers by Williamson’s synthesis.
1)1-propoxypropane- It is formed by the reaction of sodium prop oxide and 1-bromopropane. The reaction is as shown:
$C{H_3}C{H_2}CHONa + C{H_3}C{H_2}C{H_2}Br \to {C_2}{H_5}C{H_2} - O - C{H_2}{C_2}{H_5} + NaBr$
2)Sodium phenoxide and bromoethane react to give ethoxy benzene. The reaction is as shown:
3)In the third case, the reactants are sodium-2-methyl 2 prop oxide and bromoethane and the product obtained is 2-methoxy- 2-methylpropane. The reaction is as shown:
4)In the last case, sodium ethoxide and bromoethane react together to form 1-methoxyethane. The reaction is as shown:
$C{H_3}C{H_2} - ONa + C{H_3} - Br \to C{H_3}C{H_2} - O - C{H_3} + NaBr$
Note: There are few limitations of Williamson’s synthesis reaction. The tertiary alkyl halides or primary or secondary alkyl halides that are sterically impeded continue to undergo ${E_2}$ removal in the presence of alkoxide, which serves as a base in addition to being a nucleophile. Moreover, this reaction is significant in the organic chemistry history as it has helped to prove the ether structures.
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