Write the factors of the terms of the following algebraic expressions
a)$xyz - {x^3} + 2{y^3}$
b) $ - 25{x^2}y + 6x{y^2}$
Answer
593.7k+ views
Hint: A factor of an algebraic expression is a number or variable or term or a long expression that can divide the expression.
Complete step-by-step answer:
Step1:For a):
There is no divisor of the expression except 1 and the expression itself. Hence the factors of $(xyz - {x^3} + 2{y^3})$ are 1 and $(xyz - {x^3} + 2{y^3})$.
Step2:For b):
$\eqalign{
& - 25{x^2}y + 6x{y^2} \cr
& = xy(6y - 25x) \cr} $
Hence the factors of $( - 25{x^2}y + 6x{y^2})$are 1,x,y,xy,(6y-25x),x(6y-25x),y(6y-25x),xy(6y-25x).
Note: A factor may be a number or variable or term or a long expression that can divide the expression. Factors of ${x^3}\,\,are\,\,1,x,{x^2},{x^3}.$
Complete step-by-step answer:
Step1:For a):
There is no divisor of the expression except 1 and the expression itself. Hence the factors of $(xyz - {x^3} + 2{y^3})$ are 1 and $(xyz - {x^3} + 2{y^3})$.
Step2:For b):
$\eqalign{
& - 25{x^2}y + 6x{y^2} \cr
& = xy(6y - 25x) \cr} $
Hence the factors of $( - 25{x^2}y + 6x{y^2})$are 1,x,y,xy,(6y-25x),x(6y-25x),y(6y-25x),xy(6y-25x).
Note: A factor may be a number or variable or term or a long expression that can divide the expression. Factors of ${x^3}\,\,are\,\,1,x,{x^2},{x^3}.$
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