Question

Write the equation for
(i) the action of $S{O_2}$ with chlorine in the presence of charcoal

Answer 1

Hint:The process in which a substance transforms chemically into a different substance by making or breaking bonds between the atoms of the elements is known as a chemical reaction. Chemical reactions are graphically represented by chemical equations.

Complete answer:
In a chemical reaction, the initial substances which get converted are known as reactants and the final substances obtained are known as products. Chemical reactions are of various types which are as follows; synthesis reaction, decomposition reaction, displacement reaction, addition reaction, oxidation-reduction reaction and many more.
Chemical equation is a useful tool to illustrate a chemical reaction. There are certain rules to write a chemical equation. The reactants are on the left hand side and the products are on the right hand side and both reactants and products consist of chemical or structural formulas. The reactants and the products are separated by an arrow which basically is read as ‘yields’. The direction of the arrow shows the direction of the chemical reaction. Each chemical equation should be balanced in terms of stoichiometry, that is the number of atoms of each element should be equal on both the right and left hand sides.
Now, the chemical equation which should be written for the action of $S{O_2}$ with chlorine in the presence of charcoal can be given as follows,
$S{O_2}\left( g \right) + C{l_2}\left( g \right) \to S{O_2}C{l_2}\left( l \right)$
The product formed is sulphuryl chloride.

Note:
In a chemical equation, the states of the reactants and products can be written in the bracket in the form of symbols. This is not necessary or compulsory. Also, there are different types of reaction arrows. The catalyst is usually written above or below the arrow.