Write the coordinates of the vertices of each of these adjoining figures.
Answer
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Hint: We have the find the coordinates of the given points. Recall that any point on the cartesian plane is written in the form $\left( {x,y} \right)$, where $x$ coordinate is the vertical distance from the origin and $y$ coordinate is the horizontal distance from the origin.
Complete step by step solution: We have to find the coordinates of the vertices of each given figure.
The coordinates corresponding to any point is written in the form $\left( {x,y} \right)$ where $x$ is the perpendicular distance from the $y$ axis to the point and $y$ coordinate is the perpendicular distance from the $x$ axis.
Here, the numbers written on the $x$ axis represents the perpendicular distance vertically from the origin.
And the numbers written on the $y$ axis represents the perpendicular distance horizontally from the origin.
Now, let us find the coordinates of point A.
Point A has located 2 units horizontally from the origin and the 0 units vertically from the origin. Hence, the coordinates of A are \[\left( {2,0} \right)\]
As we can see point B is located 0 units horizontally from the origin and the 0 units vertically from the origin. Hence, the coordinates of B are \[\left( {0,0} \right)\]
Now, point C is located 0 units horizontally from the origin and the 0 units vertically from the origin. Hence, the coordinates of C are \[\left( {0,3} \right)\]
Here, point D is situated 2 units horizontally and 3 units vertically from the origin. Hence, the coordinates of the point D are $\left( {2,3} \right)$
Now, let us determine the coordinates of point P.
Point P is situated 4 units horizontally and 3 units vertically from the origin. Hence, the coordinates of the point P are $\left( {4,3} \right)$
Similarly, point Q is plotted 6 units horizontally and 1 unit vertically from the origin.
Hence, the coordinates of the point Q are $\left( {6,1} \right)$
Point S has plotted 4 units horizontally and 7 unit vertically from the origin.
Hence, the coordinates of the point S are $\left( {4,7} \right)$
Now, point R is at the distance of 6 units horizontal from the origin and 5 units vertical from the origin. Thus, the coordinates of R are $\left( {6,5} \right)$
The point K has plotted 10 units horizontally and 5 unit vertically from the origin.
Hence, the coordinates of the point K are $\left( {10,5} \right)$
The point L is plotted 7 units horizontally and 7 unit vertically from the origin. Hence, the coordinates of the point L are $\left( {7,7} \right)$
The point M has plotted 10 units horizontally and 8 unit vertically from the origin. Hence, the coordinates of the point K are $\left( {10,8} \right)$
Note: The coordinates are written in ordered pair, $\left( {x,y} \right)$, where $x$ is the coordinate written in the first place which is called as abscissa and $y$ coordinate is written in second place which is simply called as ordinate.
Complete step by step solution: We have to find the coordinates of the vertices of each given figure.
The coordinates corresponding to any point is written in the form $\left( {x,y} \right)$ where $x$ is the perpendicular distance from the $y$ axis to the point and $y$ coordinate is the perpendicular distance from the $x$ axis.
Here, the numbers written on the $x$ axis represents the perpendicular distance vertically from the origin.
And the numbers written on the $y$ axis represents the perpendicular distance horizontally from the origin.
Now, let us find the coordinates of point A.
Point A has located 2 units horizontally from the origin and the 0 units vertically from the origin. Hence, the coordinates of A are \[\left( {2,0} \right)\]
As we can see point B is located 0 units horizontally from the origin and the 0 units vertically from the origin. Hence, the coordinates of B are \[\left( {0,0} \right)\]
Now, point C is located 0 units horizontally from the origin and the 0 units vertically from the origin. Hence, the coordinates of C are \[\left( {0,3} \right)\]
Here, point D is situated 2 units horizontally and 3 units vertically from the origin. Hence, the coordinates of the point D are $\left( {2,3} \right)$
Now, let us determine the coordinates of point P.
Point P is situated 4 units horizontally and 3 units vertically from the origin. Hence, the coordinates of the point P are $\left( {4,3} \right)$
Similarly, point Q is plotted 6 units horizontally and 1 unit vertically from the origin.
Hence, the coordinates of the point Q are $\left( {6,1} \right)$
Point S has plotted 4 units horizontally and 7 unit vertically from the origin.
Hence, the coordinates of the point S are $\left( {4,7} \right)$
Now, point R is at the distance of 6 units horizontal from the origin and 5 units vertical from the origin. Thus, the coordinates of R are $\left( {6,5} \right)$
The point K has plotted 10 units horizontally and 5 unit vertically from the origin.
Hence, the coordinates of the point K are $\left( {10,5} \right)$
The point L is plotted 7 units horizontally and 7 unit vertically from the origin. Hence, the coordinates of the point L are $\left( {7,7} \right)$
The point M has plotted 10 units horizontally and 8 unit vertically from the origin. Hence, the coordinates of the point K are $\left( {10,8} \right)$
Note: The coordinates are written in ordered pair, $\left( {x,y} \right)$, where $x$ is the coordinate written in the first place which is called as abscissa and $y$ coordinate is written in second place which is simply called as ordinate.
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