
Write the chemical equation of the reaction in which the following changes have taken place with an example of each.
i) Change in colour
ii) Change in temperature
iii) formation of precipitate
Answer
498.9k+ views
Hint: In chemistry, equations play a major role. In the reaction three things are main. There are reactant, product and reaction conditions. The reactants are always on the left side of the equation. If more than one reactant in the equation means by using plus sign. The products are always on the right side of the reaction. Something here also follows. More than one product by using plus sign. In between reactant products are used arrows to find the reaction direction in the equation.
Complete answer:
The chemical equation of the reaction in the following changes have taken place with an condition is given below,
i) Change in colour
\[{\text{Pb(N}}{{\text{O}}_{\text{3}}}{{\text{)}}_{\text{2}}}{\text{ + 2KI}} \to {\text{Pb}}{{\text{I}}_{\text{2}}}{\text{ + 2KN}}{{\text{O}}_{\text{3}}}\]
Lead nitrate reacts with potassium iodide to give lead iodide as a product. The reaction mass changes colour from colourless to yellow colour spangles due to lead iodide.
ii) Change in temperature
Zinc is reacted with sulphuric acid to give zinc sulphate as product and evolution of hydrogen. The evolution of hydrogen gives energy from heat, and temperature will increase.
\[{\text{Zn + }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} \to {\text{ZnS}}{{\text{O}}_{\text{4}}}{\text{ + }}{{\text{H}}_{\text{2}}}\]
iii) Formation of precipitate
\[{\text{NaOH + }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} \to {\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\]
Sodium hydroxide is reacted with sulphuric acid to give sodium sulphate as a precipitated product in water.
Note:
In balanced chemical reaction wise, we predict the side product of the reaction. In some cases we are not able to attain the balance by changing the mole. In that case we use the number of countable ions in the product and reactant side of the chemical reaction. In chemistry, redox reaction is one of the types of major reactions. In this redox reaction two methods are used to attain the balanced chemical reaction. There are ion-electron methods and the oxidation number method.
Complete answer:
The chemical equation of the reaction in the following changes have taken place with an condition is given below,
i) Change in colour
\[{\text{Pb(N}}{{\text{O}}_{\text{3}}}{{\text{)}}_{\text{2}}}{\text{ + 2KI}} \to {\text{Pb}}{{\text{I}}_{\text{2}}}{\text{ + 2KN}}{{\text{O}}_{\text{3}}}\]
Lead nitrate reacts with potassium iodide to give lead iodide as a product. The reaction mass changes colour from colourless to yellow colour spangles due to lead iodide.
ii) Change in temperature
Zinc is reacted with sulphuric acid to give zinc sulphate as product and evolution of hydrogen. The evolution of hydrogen gives energy from heat, and temperature will increase.
\[{\text{Zn + }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} \to {\text{ZnS}}{{\text{O}}_{\text{4}}}{\text{ + }}{{\text{H}}_{\text{2}}}\]
iii) Formation of precipitate
\[{\text{NaOH + }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} \to {\text{N}}{{\text{a}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}}\]
Sodium hydroxide is reacted with sulphuric acid to give sodium sulphate as a precipitated product in water.
Note:
In balanced chemical reaction wise, we predict the side product of the reaction. In some cases we are not able to attain the balance by changing the mole. In that case we use the number of countable ions in the product and reactant side of the chemical reaction. In chemistry, redox reaction is one of the types of major reactions. In this redox reaction two methods are used to attain the balanced chemical reaction. There are ion-electron methods and the oxidation number method.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

