
Write the additive inverse of $\dfrac{-11}{5}?$
Answer
467.1k+ views
Hint: We know that a number when added to its additive inverse provides zero as their sum. So, to find the additive inverse of a number, we need to find the number that can provide us with zero when they are added. We will subtract the number from zero to find its additive inverse.
Complete step-by-step solution:
Let us consider the given number $\dfrac{-11}{5}.$
We are asked to find the additive inverse of the given number.
We know that the sum of a number and its additive inverse is zero.
So, to find the opposite of the given number, we will find the number which can be added to the given number to provide zero.
Let us suppose that $x$ is the additive inverse of the given number $\dfrac{-11}{5}.$
Then we will get $\dfrac{-11}{5}+x=0.$
Now, we need to transpose the constant term from the left-hand side to the right-hand side of the above equation.
As we know, while we transpose a number, we need to change the sign of the number from negative to positive or vice versa. In this case, we can see the sign is negative.
So, we will get $x=0+\dfrac{11}{5}=\dfrac{11}{5}.$
Therefore, we will get $x=\dfrac{11}{5}.$
From this, we can learn that the additive inverse of a number can be found by multiplying the number with $-1.$
Hence the additive inverse of the given number is $\dfrac{11}{5}.$
Note: If we want to find the multiplicative inverse of a number, we need to take the reciprocal of the number. If the number is an integer, then the numerator will be $1$ and the denominator will be the number itself. If the number is a fraction, then we need to interchange the numerator and the denominator to get the multiplicative inverse.
Complete step-by-step solution:
Let us consider the given number $\dfrac{-11}{5}.$
We are asked to find the additive inverse of the given number.
We know that the sum of a number and its additive inverse is zero.
So, to find the opposite of the given number, we will find the number which can be added to the given number to provide zero.
Let us suppose that $x$ is the additive inverse of the given number $\dfrac{-11}{5}.$
Then we will get $\dfrac{-11}{5}+x=0.$
Now, we need to transpose the constant term from the left-hand side to the right-hand side of the above equation.
As we know, while we transpose a number, we need to change the sign of the number from negative to positive or vice versa. In this case, we can see the sign is negative.
So, we will get $x=0+\dfrac{11}{5}=\dfrac{11}{5}.$
Therefore, we will get $x=\dfrac{11}{5}.$
From this, we can learn that the additive inverse of a number can be found by multiplying the number with $-1.$
Hence the additive inverse of the given number is $\dfrac{11}{5}.$
Note: If we want to find the multiplicative inverse of a number, we need to take the reciprocal of the number. If the number is an integer, then the numerator will be $1$ and the denominator will be the number itself. If the number is a fraction, then we need to interchange the numerator and the denominator to get the multiplicative inverse.
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