
Write IUPAC names of the following compounds.
(i) \[C{{H}_{3}}-C{{H}_{2}}-\underset{\overset{|}{\mathop C{{H}_{3}}}\,}{\overset{\underset{|}{\mathop C{{H}_{3}}}\,}{\mathop{C}}}\,-C{{H}_{2}}-Cl\]
(ii) \[C{{H}_{2}}=CHCl\]
Answer
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Hint: In the question structures of organic compounds are given. And we start the naming from the substituents. If you look at this question compound, here substituents and double bonds both are present.
Step by step solution:
IUPAC: International Union of Pure and Applied Chemistry
IUPAC is an acronym for International Union of Pure and Applied Chemistry, which is a globally recognized international chemistry standards organization that has named all the chemical organic substances in a systematic manner.
Given:
(i) \[C{{H}_{3}}-C{{H}_{2}}-\underset{\overset{|}{\mathop C{{H}_{3}}}\,}{\overset{\underset{|}{\mathop C{{H}_{3}}}\,}{\mathop{C}}}\,-C{{H}_{2}}-Cl\]
(ii) \[C{{H}_{2}}=CHCl\]
For the IUPAC naming of these compounds:
- First we select the main chain or parent chain which has the maximum number of carbon atoms (4 membered carbon chain in (i) compound and 2 membered carbon chain in (ii)),
- Then we will see the number and position of substituent and do their numbering in the order of preference. Here, 3 substituents (two methyl groups and one chlorine) in (i) compound and one substituent (chlorine) in (ii) compound.
- Then we will see for the suffix and prefix, and here parent chain is a four membered chain in (i) compound so ‘but’ prefix will be used and double bond is present in (ii) compound so ‘ene’ prefix will be used.
Now we will check the position of double bonds and substituents. So in (i) we will start the numbering from the end where chlorine is attached and in (ii) compound we will start numbering from the end where chlorine is attached.
\[\underset{4}{\mathop{C{{H}_{3}}}}\,-\underset{3}{\mathop{C{{H}_{2}}}}\,-\underset{\overset{|2}{\mathop C{{H}_{3}}}\,}{\overset{\underset{|}{\mathop C{{H}_{3}}}\,}{\mathop{C}}}\,-\underset{1}{\mathop{C{{H}_{2}}}}\,-Cl\]
\[C{{H}_{2}}=\underset{1}{\mathop{C}}\,HCl\]
So, the IUPAC names of compounds are:
1-chloro-2-dimethylbutane
1-chloro-1-ethene
Note: In this compound there were both substituent and double bond, but are at the same position. If the substituents and double bonds are given at different positions then we will do the numbering according to the preference of substituents or bonds or functional group.
Step by step solution:
IUPAC: International Union of Pure and Applied Chemistry
IUPAC is an acronym for International Union of Pure and Applied Chemistry, which is a globally recognized international chemistry standards organization that has named all the chemical organic substances in a systematic manner.
Given:
(i) \[C{{H}_{3}}-C{{H}_{2}}-\underset{\overset{|}{\mathop C{{H}_{3}}}\,}{\overset{\underset{|}{\mathop C{{H}_{3}}}\,}{\mathop{C}}}\,-C{{H}_{2}}-Cl\]
(ii) \[C{{H}_{2}}=CHCl\]
For the IUPAC naming of these compounds:
- First we select the main chain or parent chain which has the maximum number of carbon atoms (4 membered carbon chain in (i) compound and 2 membered carbon chain in (ii)),
- Then we will see the number and position of substituent and do their numbering in the order of preference. Here, 3 substituents (two methyl groups and one chlorine) in (i) compound and one substituent (chlorine) in (ii) compound.
- Then we will see for the suffix and prefix, and here parent chain is a four membered chain in (i) compound so ‘but’ prefix will be used and double bond is present in (ii) compound so ‘ene’ prefix will be used.
Now we will check the position of double bonds and substituents. So in (i) we will start the numbering from the end where chlorine is attached and in (ii) compound we will start numbering from the end where chlorine is attached.
\[\underset{4}{\mathop{C{{H}_{3}}}}\,-\underset{3}{\mathop{C{{H}_{2}}}}\,-\underset{\overset{|2}{\mathop C{{H}_{3}}}\,}{\overset{\underset{|}{\mathop C{{H}_{3}}}\,}{\mathop{C}}}\,-\underset{1}{\mathop{C{{H}_{2}}}}\,-Cl\]
\[C{{H}_{2}}=\underset{1}{\mathop{C}}\,HCl\]
So, the IUPAC names of compounds are:
1-chloro-2-dimethylbutane
1-chloro-1-ethene
Note: In this compound there were both substituent and double bond, but are at the same position. If the substituents and double bonds are given at different positions then we will do the numbering according to the preference of substituents or bonds or functional group.
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