
How do you write $\dfrac{9}{{20}}$ as a decimal?
Answer
465.9k+ views
Hint:
Though this problem is straightforward, one trick to solve such sums is by converting them to the nearest $100s$. By doing this the student will not have to sit and divide the numerator and the denominator. Chances of going wrong are also very less. The first step is to find the nearest $100s$ for $20$. After that, the student has to multiply the numerator and denominator by the same number so that the denominator has $100$ or it’s multiple. After this step, the student will just have to input the decimal point to get the final answer.
Complete Step by Step Solution:
The first step is to find the nearest multiple of $100$.
Since $20$ is close to $100$, we will convert $20$ to $100$ by multiplying it with $5$
Multiplying by $5$ to both numerator and denominator , we get
$\dfrac{9}{{20}} = \dfrac{9}{{20}} \times \dfrac{5}{5}.............(1)$
$\dfrac{9}{{20}} = \dfrac{{45}}{{100}} = 0.45............(2)$
From equation $2$we can say that the decimal value for $\dfrac{9}{{20}}$is$0.45$.
Note:
This numerical is very simple if it is done by this method. Otherwise in the case of a complex numerical for example $\dfrac{{353}}{{250}}$, if the student sits and divides the numerator and denominator, he may consume a lot of time. On the contrary, just multiplying the numerator and denominator by a common multiple would solve the sum faster. Thus the students are always advised to bring the numerator in terms of its nearest $100th$ multiple and then convert the number to decimal. Also, the chances of making errors by following this method are less compared to direct division.
Though this problem is straightforward, one trick to solve such sums is by converting them to the nearest $100s$. By doing this the student will not have to sit and divide the numerator and the denominator. Chances of going wrong are also very less. The first step is to find the nearest $100s$ for $20$. After that, the student has to multiply the numerator and denominator by the same number so that the denominator has $100$ or it’s multiple. After this step, the student will just have to input the decimal point to get the final answer.
Complete Step by Step Solution:
The first step is to find the nearest multiple of $100$.
Since $20$ is close to $100$, we will convert $20$ to $100$ by multiplying it with $5$
Multiplying by $5$ to both numerator and denominator , we get
$\dfrac{9}{{20}} = \dfrac{9}{{20}} \times \dfrac{5}{5}.............(1)$
$\dfrac{9}{{20}} = \dfrac{{45}}{{100}} = 0.45............(2)$
From equation $2$we can say that the decimal value for $\dfrac{9}{{20}}$is$0.45$.
Note:
This numerical is very simple if it is done by this method. Otherwise in the case of a complex numerical for example $\dfrac{{353}}{{250}}$, if the student sits and divides the numerator and denominator, he may consume a lot of time. On the contrary, just multiplying the numerator and denominator by a common multiple would solve the sum faster. Thus the students are always advised to bring the numerator in terms of its nearest $100th$ multiple and then convert the number to decimal. Also, the chances of making errors by following this method are less compared to direct division.
Recently Updated Pages
Out of 30 students in a class 6 like football 12 like class 7 maths CBSE

Earth rotates from West to east ATrue BFalse class 6 social science CBSE

The easternmost longitude of India is A 97circ 25E class 6 social science CBSE

Write the given sentence in the passive voice Ann cant class 6 CBSE

Convert 1 foot into meters A030 meter B03048 meter-class-6-maths-CBSE

What is the LCM of 30 and 40 class 6 maths CBSE

Trending doubts
How many millions make a billion class 6 maths CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Four bells toll together at 900am They toll after 7811 class 6 maths CBSE

The forces of Alexander and Porus fought on the banks class 6 social science CBSE

Write short notes on the island groups of India class 6 social science CBSE

Where was Kalpana Chawla born Why is she called an class 6 english CBSE
