How do you write an equation in standard form given point $\left( {0,0} \right)$ and slope $\dfrac{1}{3}$.
Answer
582k+ views
Hint: As the point and the slope of the line is given. First, substitute the point and slope in the slope-intercept formula, $y = mx + c$ to find the y-intercept. After that use the slope and y-intercept to find the equation of the line. Then move all variables on one side and the constant on another side as $Ax + By = C$ to make the equation in standard form.
Complete step-by-step answer:
The given point is $\left( {0,0} \right)$ and the slope is $\dfrac{1}{3}$.
As we know that the equation of the line in slope-intercept form is,
$y = mx + c$
Where,
m is the slope of the line and c is the y-intercept.
Substituting the point $\left( {0,0} \right)$ and the slope $\dfrac{1}{3}$ in slope-intercept form, we get
$ \Rightarrow 0 = \dfrac{1}{3} \times 0 + c$
On simplifying the terms, we get
$ \Rightarrow c = 0$
Now, we have a slope $m = \dfrac{1}{3}$ and y-intercept $c = 0$.
Use these values to find the equation of the line.
Substitute these values in slope-intercept form,
$ \Rightarrow y = \dfrac{1}{3}x + 0$
Simplify the terms,
$ \Rightarrow y = \dfrac{1}{3}x$
Multiply both sides by 3 to remove the rational part,
$ \Rightarrow 3y = x$
So, the equation of the line is $x = 3y$.
Now, we have to write the equation in standard form.
The standard equation or general form of linear equation with two variables is,
$Ax + By = C$
Where A, B, C are real numbers while x and y are variables. Here, A and B are not equal to zero.
Now, subtract $3y$ from both sides,
$ \Rightarrow x - 3y = 3y - 3y$
On simplifying the terms, we get
$\therefore x - 3y = 0$
Hence, the equation in standard form is $x - 3y = 0$.
Note:
Linear equation represents a straight line. Linear equations in two variables make it easy to explain the geometry of lines or the graph of two lines of equations. It contains two variables whose values are unknown.
It contains values of x and y both as a solution to make the two sides of the equation equal.
The linear equations of two variables are often used in the following ways–
The problems can be solved by converting the situation into mathematical statements that tell the relation between the unknown variables. It makes it easier to solve such problems.
It is mainly used in linear programming problems called LPPs which involve analytical thinking and it deals with real-life situations.
Complete step-by-step answer:
The given point is $\left( {0,0} \right)$ and the slope is $\dfrac{1}{3}$.
As we know that the equation of the line in slope-intercept form is,
$y = mx + c$
Where,
m is the slope of the line and c is the y-intercept.
Substituting the point $\left( {0,0} \right)$ and the slope $\dfrac{1}{3}$ in slope-intercept form, we get
$ \Rightarrow 0 = \dfrac{1}{3} \times 0 + c$
On simplifying the terms, we get
$ \Rightarrow c = 0$
Now, we have a slope $m = \dfrac{1}{3}$ and y-intercept $c = 0$.
Use these values to find the equation of the line.
Substitute these values in slope-intercept form,
$ \Rightarrow y = \dfrac{1}{3}x + 0$
Simplify the terms,
$ \Rightarrow y = \dfrac{1}{3}x$
Multiply both sides by 3 to remove the rational part,
$ \Rightarrow 3y = x$
So, the equation of the line is $x = 3y$.
Now, we have to write the equation in standard form.
The standard equation or general form of linear equation with two variables is,
$Ax + By = C$
Where A, B, C are real numbers while x and y are variables. Here, A and B are not equal to zero.
Now, subtract $3y$ from both sides,
$ \Rightarrow x - 3y = 3y - 3y$
On simplifying the terms, we get
$\therefore x - 3y = 0$
Hence, the equation in standard form is $x - 3y = 0$.
Note:
Linear equation represents a straight line. Linear equations in two variables make it easy to explain the geometry of lines or the graph of two lines of equations. It contains two variables whose values are unknown.
It contains values of x and y both as a solution to make the two sides of the equation equal.
The linear equations of two variables are often used in the following ways–
The problems can be solved by converting the situation into mathematical statements that tell the relation between the unknown variables. It makes it easier to solve such problems.
It is mainly used in linear programming problems called LPPs which involve analytical thinking and it deals with real-life situations.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

