
How do you write $ - 12x - 2y \geqslant 42 $ in slope-intercept form?
Answer
549.6k+ views
Hint: In order to determine the slope and intercept to the above inequality, we have to rewrite the inequality such that the LHS of the inequality contain only the $ y $ term by applying some operations. Add $ + 12x $ on both sides, then divide the both sides with the number $ - 2 $ but remember to reverse the inequality symbol to maintain the balance. Compare the result with the slope-intercept form $ y = mx + c $ , m is the slope and c is the y-intercept.
Complete step-by-step answer:
We are given a linear inequality in two variables $ x\,and\,y $ i.e. $ - 12x - 2y \geqslant 42 $
The slope-intercept of a linear equation is $ y = mx + c $ , where m is the slope of the line and c is the y-intercept of the graph.
Since, we are given a linear inequality, we have to rewrite the inequality in such a way that it can be comparable with the slope intercept form.
And do so we have to make the LHS of the inequality contain only the $ y $ term by applying some operations.
$ - 12x - 2y \geqslant 42 $
Adding both sides of the inequality with $ + 12x $ . Remember that addition of any positive term on both sides of inequality does not affect the symbol of inequality.
$
- 12x - 2y + 12x \geqslant 42 + 12x \\
- 2y \geqslant 12x + 42 \;
$
Now dividing both sides of the inequality with the coefficient of variable $ y $ i.e. \[ - 2\].But wait , recall the rule of inequality that when a negative term is divided on both sides it disbalances the inequality. So, to balance it again we have to reverse the symbol of inequality as from $ \geqslant \,to\, \leqslant $ .
$
\dfrac{{ - 2y}}{{ - 2}} \leqslant \dfrac{{12x + 42}}{{ - 2}} \\
y \leqslant - \dfrac{{12x}}{2} - \dfrac{{42}}{2} \\
y \leqslant - 6x - 21 \\
$
Comparing the above with slope-intercept form $ y = mx + c $
So $
m = - 6 \\
c = - 21 \;
$
Therefore the required slope-intercept form is $ y \leqslant - 6x - 21 $ with slope $ m = - 6 $ and intercept as $ c = - 21 $
So, the correct answer is “ $ c = - 21 $ ”.
Note: 1. Graph of the inequality given in this question will have solid line as it contains the Slack inequality $ \left( { \geqslant , \leqslant } \right) $
2.Slope of line perpendicular to the line having slope $ m $ is equal to $ - \dfrac{1}{m} $ .
3.when a negative term is added on both sides then also the inequality symbol gets reversed.
Complete step-by-step answer:
We are given a linear inequality in two variables $ x\,and\,y $ i.e. $ - 12x - 2y \geqslant 42 $
The slope-intercept of a linear equation is $ y = mx + c $ , where m is the slope of the line and c is the y-intercept of the graph.
Since, we are given a linear inequality, we have to rewrite the inequality in such a way that it can be comparable with the slope intercept form.
And do so we have to make the LHS of the inequality contain only the $ y $ term by applying some operations.
$ - 12x - 2y \geqslant 42 $
Adding both sides of the inequality with $ + 12x $ . Remember that addition of any positive term on both sides of inequality does not affect the symbol of inequality.
$
- 12x - 2y + 12x \geqslant 42 + 12x \\
- 2y \geqslant 12x + 42 \;
$
Now dividing both sides of the inequality with the coefficient of variable $ y $ i.e. \[ - 2\].But wait , recall the rule of inequality that when a negative term is divided on both sides it disbalances the inequality. So, to balance it again we have to reverse the symbol of inequality as from $ \geqslant \,to\, \leqslant $ .
$
\dfrac{{ - 2y}}{{ - 2}} \leqslant \dfrac{{12x + 42}}{{ - 2}} \\
y \leqslant - \dfrac{{12x}}{2} - \dfrac{{42}}{2} \\
y \leqslant - 6x - 21 \\
$
Comparing the above with slope-intercept form $ y = mx + c $
So $
m = - 6 \\
c = - 21 \;
$
Therefore the required slope-intercept form is $ y \leqslant - 6x - 21 $ with slope $ m = - 6 $ and intercept as $ c = - 21 $
So, the correct answer is “ $ c = - 21 $ ”.
Note: 1. Graph of the inequality given in this question will have solid line as it contains the Slack inequality $ \left( { \geqslant , \leqslant } \right) $
2.Slope of line perpendicular to the line having slope $ m $ is equal to $ - \dfrac{1}{m} $ .
3.when a negative term is added on both sides then also the inequality symbol gets reversed.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

