Question

Which statement is incorrect for $$OS{F}_4$$?
A.S atom has $$s{p}^{3}d$$ hybridization
B.$$OS{F}_4$$have distorted trigonal pyramidal geometry
C.O atom at one of the two axial positions having S=O bond
D.O atom at one of the two equatorial position having S=O bond

Answer 1

Hint: To solve this question, we must find the electronic configuration and then the hybridization. From this, we would be able to conclude the geometry of the molecule and then we can cross check the options given to us.

Complete Step-by-Step Answer:
Before we move forward with the solution of the given question, let us first understand some important basic concepts.
Let us first try to identify the hybridisation of the sulphur atom used and then in accordance to that, let us find the geometrical structure of the given compound.
Now, in the given compound, sulphur is the central atom. The atomic number of sulphur is 16. Hence, its electronic configuration can be given as: $$1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}3d^0$$. Thus, we can see that there are 6 electrons present in the valence shell and these electrons are divided between the 3s and 3p subshells. The electrons in the valence shell can be represented as:

Now, we need to add 5 substituents to the sulphur atom to form $$OS{F}_4$$, viz. 4 atoms of fluorine and one atom of oxygen. To form the sites for adding these substituents, the negative spinning electrons are transferred from their subshells to the ‘d’ subshell. Since 2 electrons are added to the ‘d’ orbital.

Now, one of the d orbital electrons will be required to form pi bonds with oxygen. Hence, the effective hybridization of the sulphur atom is $$s{p}^{3}d$$. Now, we have zero lone pairs, 5 sigma bonds and one pi bond present in the structure. Hence the corresponding geometric structure of $$OS{F}_4$$ is trigonal bipyramidal. Hence the structure of $$OS{F}_4$$ is given as:

Hence, we can see that the oxygen is at the equatorial position.

Hence, Option C is the correct option

Note: Axial bonds can be understood as the bonds that are usually formed along the vertical axis of the central atom. On the other hand, equatorial bonds are formed at right angles to the axis of the central atom.