Question

Which one has the same electron configuration as a neon atom?
A.$N{a^ + }$
B.Al
C.F
D.Ti
E.$B{r^ - }$

Answer 1

Hint: Neon is the tenth element with a total of 10 electrons. In writing the electron configuration for neon the first two electrons will go in the 2p orbital. Since 1s can only hold two electrons for Ne go in the 2s orbital. The remaining six electrons will go in the 2p orbital. Therefore, the Ne electron configuration $1{s^2}2{s^2}2{p^6}$ . Here we see the element which has the same configuration of neon.

Complete step by step answer:
Ne (atomic number=10) have 2,8 electron configurations. Here the atomic number of Na is 11. The configuration of Na is 2,8,1. Atomic number of $N{a^ + }$ is 10 and it has an electron configuration of 2,8 which is similar to Ne.
Ne is an ideal gas. The configuration notation provides an easy way how electrons are arranged around the nucleus of an atom. This makes it easier to understand and predict how atoms will interact to form chemical bonds.
 $N{a^ + }$ are positively charged particles, because they are missing one electron. Other ions are negatively charged. Cells have membranes that are made of lipid molecules and prevent most things from entering or leaving the cell.

That’s why option (A) is the correct answer.

Note: Here we remember the electron configuration of the element. When it removes an electron it becomes a positive ion and if it takes an electron, it becomes a negative ion. Na is a symbol of normal sodium which contains 11 protons and 11 electrons but $N{a^ + }$ has 10 electrons which is as well as Ne.