Which of the following statements is incorrect?
a.) The frequency of radiation is inversely proportional to its wavelength.
b.) The energy of radiation increases with an increase in frequency.
c.) The energy of radiation decreases with an increase in wavelength.
d.) The frequency of radiation is directly proportional to its wavelength.
Answer
642.3k+ views
Hint: Wavelength is the distance between identical points in the adjacent cycles of a waveform signal propagated in space or along a wire. Wavelength is inversely related to frequency. The higher the frequency of the signal, the shorter the wavelength.
Complete step by step solution:
Wavelength is inversely proportional to the frequency of the wave. The waves with higher frequencies have shorter wavelengths, and lower frequencies have longer wavelengths.
As we know that, E=hν
Where, E = Energy of the radiation
h = Planck’s constant
${ \mu }$ = frequency of radiation
As we see the energy of the radiation is directly proportional to the frequency of the radiation. Hence, we can say that as the energy of radiation increases, the frequency also increases and vice versa.
As we know, ${ E=h\upsilon =hc\div \lambda }$
Where, E = Energy of the radiation
h = Planck’s constant
${ \mu }$ = frequency of radiation
${\lambda}$ = wavelength of the radiation
Energy is directly proportional to frequency and frequency is inversely proportional to the wavelength of the radiation. So, as the energy decreases, wavelength increases and vice versa as the energy of the radiation is inversely proportional to the wavelength of the radiation.
${ \upsilon =c\div \lambda }$
where, ${ \mu }$ = frequency of radiation
${\lambda}$ = wavelength of the radiation
c =speed of light
From here, we see that frequency of the radiation is inversely proportional to the wavelength of the radiation. So, the above statement is incorrect.
So, the correct answer is “Option D”.
Note: The possibility to make a mistake is that you may confuse between A and D. But as we know the frequency of the radiation is inversely proportional to the frequency of the radiation, so option D has an incorrect statement.
Complete step by step solution:
Wavelength is inversely proportional to the frequency of the wave. The waves with higher frequencies have shorter wavelengths, and lower frequencies have longer wavelengths.
As we know that, E=hν
Where, E = Energy of the radiation
h = Planck’s constant
${ \mu }$ = frequency of radiation
As we see the energy of the radiation is directly proportional to the frequency of the radiation. Hence, we can say that as the energy of radiation increases, the frequency also increases and vice versa.
As we know, ${ E=h\upsilon =hc\div \lambda }$
Where, E = Energy of the radiation
h = Planck’s constant
${ \mu }$ = frequency of radiation
${\lambda}$ = wavelength of the radiation
Energy is directly proportional to frequency and frequency is inversely proportional to the wavelength of the radiation. So, as the energy decreases, wavelength increases and vice versa as the energy of the radiation is inversely proportional to the wavelength of the radiation.
${ \upsilon =c\div \lambda }$
where, ${ \mu }$ = frequency of radiation
${\lambda}$ = wavelength of the radiation
c =speed of light
From here, we see that frequency of the radiation is inversely proportional to the wavelength of the radiation. So, the above statement is incorrect.
So, the correct answer is “Option D”.
Note: The possibility to make a mistake is that you may confuse between A and D. But as we know the frequency of the radiation is inversely proportional to the frequency of the radiation, so option D has an incorrect statement.
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