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Which of the following species are stabilized by removal of electrons?
A.NO
B.O2
C.F2
D.CN

Answer
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Hint: Bond order is the number of the chemical bonds indicated by the chemical bonds between the pair of atoms and the stability is depicted by the bond order.
For the molecules showing the resonance, the bond order may not be an integer. The pi electrons involved in the delocalisation of the charge on the molecules resulting in the resonance in the molecule are the criteria essentially directing the molecule’s bond order not exactly equal to the integer.

Complete answer:
The bond order is calculated by the difference between the electrons in the bonding and the anti- bonding orbitals.
Bond Order=Number of bonding electrons - Number of antibonding electrons2
Higher the bond order higher will be the bond energy.
That is: Bond Order Directly proportional to Bond Energy
The bond order is given below for different species as:
NO=832=2.5
O2=842=2
F2=972=1
CN=832=2.5
On the removal of one more electron from them the Bond order will change as follows:
NO=822=3
O2=832=2.5
F2=962=1.5
CN=842=2
It is evident that when the bond order will increase it will lead to the stabilisation of the molecule and when the bond order will decrease it will lead to the destabilisation of the molecules. From the above it is clear that the bond order of only CN decreases on the removal of the electron whereas for NO, O2 and F2 the bond order increases which stabilises the molecule .Thus all of them will be stabilised by the removal of the electrons.

Thus option A., B. and C. is the correct answer.

Note:
The measure of the bond strength is known as the bond energy. The energy is to be given to the system in order to convert the one mole of any molecule into the constituent atoms. It is the measure of the gained stability when the atoms are bonded to each other.