Question

Which of the following is/are divisible by $10$?
A.$10$
B.$200$
C.$300$
D.All of the above

Answer 1

Hint: In order to find the numbers which is/are divisible by $10$, we should know the divisibility rule of $10$, which says that a number is completely divisible by $10$, if we divide them by $10$ and we get a remainder $0$. So, for the question given, check out the options one by one by dividing them by $10$ and check whether we get $0$ as a remainder or not.
Formula used:
$Dividend = Divisor \times Quotient + \operatorname{Re} mainder$

Complete answer: We are given four numbers and we need to check which of the following numbers is divisible by $10$. For that we know that a number is divisible by completely divisible by some number, if we divide them and we get a remainder zero.
For the above question, we need to check which number when divided by $10$ gives $0$ as remainder.
So, we will check for all four options, by splitting the term as:
$Dividend = Divisor \times Quotient + \operatorname{Re} mainder$
Option 1:
When we divide $10$ by $10$, we get:
$ \Rightarrow 10 = 10 \times 1 + 0$
Since, the remainder is $0$, so Option 1 is correct and it is divisible by $10$.
Option 2:
When we divide $200$ by $10$, we get:
$ \Rightarrow 200 = 10 \times 20 + 0$
Since, the remainder is $0$, so Option 2 is correct and it is divisible by $10$.
 Option 3:
When we divide $300$ by $10$, we get:
$ \Rightarrow 300 = 10 \times 30 + 0$
Since, the remainder is $0$, so Option 3 is correct and it is divisible by $10$.
Since, all three options are correct, so we will choose the fourth option that is All of the above.
Hence, the correct option is Option D.

Note:
Remember, there are different divisibility rules that are followed for checking divisibility of a number, such as a number to be divisible by $2$ must have an even number at the end, a number having $5$ at its ending is always divisible by $5$, and any number that ends with $0$ is always divisible by $2,5$ and $10$, etc.