Answer
Verified
437.4k+ views
Hint: The reagent \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] and \[{\text{HCl}}\] used to distinguish primary, secondary and tertiary amines. Only primary aliphatic amines react with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] and \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\] . The product of the reaction is alcohol.
Complete Step by step answer: The reagent given to us is \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] and \[{\text{HCl}}\] and the reaction condition is \[{\text{0 - 4}}^\circ {\text{C}}\]. Only primary aliphatic amines react with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] and \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\] and give alcohol as the product.
The amine given in option A is \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]. Its structure is as follows:
It is aromatic amine so it will not give phenol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
Thus, option (A) \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\] is incorrect.
The amine given in option B is\[{{\text{C}}_2}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]. Its structure is as follows:
It is a primary aliphatic amine so it will give alcohol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
So, option (B) \[{{\text{C}}_2}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]is correct.
The amine given in option C is \[{\text{C}}{{\text{H}}_3}{\text{NHC}}{{\text{H}}_3}\]. Its structure is as follows:
It is secondary aliphatic amine so it will not give alcohol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
Thus, option (C) \[{\text{C}}{{\text{H}}_3}{\text{NHC}}{{\text{H}}_3}\] is incorrect.
The amine given in option D is \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{NHC}}{{\text{H}}_{\text{3}}}\]. Its structure is as follows:
It is aromatic secondary amine so it will not give phenol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
Thus, option (D) \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{NHC}}{{\text{H}}_{\text{3}}}\] is incorrect.
Hence, option (B) \[{{\text{C}}_2}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]is the correct answer.
Note: Aliphatic primary amines react with\[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\]and undergo diazotization to form alkane diazonium salt, which however being unstable decomposes to form a mixture of alcohols, alkene with the liberation of \[{{\text{N}}_{\text{2}}}\] gas. Secondary amines react with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] to form N-nitrosamines.
Complete Step by step answer: The reagent given to us is \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] and \[{\text{HCl}}\] and the reaction condition is \[{\text{0 - 4}}^\circ {\text{C}}\]. Only primary aliphatic amines react with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] and \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\] and give alcohol as the product.
The amine given in option A is \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]. Its structure is as follows:
It is aromatic amine so it will not give phenol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
Thus, option (A) \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\] is incorrect.
The amine given in option B is\[{{\text{C}}_2}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]. Its structure is as follows:
It is a primary aliphatic amine so it will give alcohol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
So, option (B) \[{{\text{C}}_2}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]is correct.
The amine given in option C is \[{\text{C}}{{\text{H}}_3}{\text{NHC}}{{\text{H}}_3}\]. Its structure is as follows:
It is secondary aliphatic amine so it will not give alcohol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
Thus, option (C) \[{\text{C}}{{\text{H}}_3}{\text{NHC}}{{\text{H}}_3}\] is incorrect.
The amine given in option D is \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{NHC}}{{\text{H}}_{\text{3}}}\]. Its structure is as follows:
It is aromatic secondary amine so it will not give phenol after reacting with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\].
Thus, option (D) \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{5}}}{\text{NHC}}{{\text{H}}_{\text{3}}}\] is incorrect.
Hence, option (B) \[{{\text{C}}_2}{{\text{H}}_{\text{5}}}{\text{N}}{{\text{H}}_{\text{2}}}\]is the correct answer.
Note: Aliphatic primary amines react with\[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] at \[{\text{0 - 4}}^\circ {\text{C}}\]and undergo diazotization to form alkane diazonium salt, which however being unstable decomposes to form a mixture of alcohols, alkene with the liberation of \[{{\text{N}}_{\text{2}}}\] gas. Secondary amines react with \[{\text{NaN}}{{\text{O}}_{\text{2}}}\] in \[{\text{HCl}}\] to form N-nitrosamines.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE