
What is the octet rule of nitrogen?
Answer
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Hint: We have to know that the octet rule alludes to the propensity of molecules to like to have eight electrons in the valence shell. At the point when molecules have less than eight electrons, they will in general respond and frame more steady mixtures.
Complete answer:
The octet rule is the understanding that most atoms seek to gain stability in their outermost energy level by filling the $s$ and $p$ orbitals of the highest energy level with eight electrons.
We have to know that the nitrogen has an electron configuration of $1{s^2}2{s^2}2{p^3}$ this means that nitrogen has five valence electrons $2{s^2}2{p^3}$. Nitrogen seeks out three additional electrons to fill the $p$ orbital and gain the stability of a noble gas, $1{s^2}2{s^2}2{p^6}$. However, now nitrogen has ten electrons and only seven protons making it a $ - 3$ charge anion ${N^{ - 3}}$.
Additional information:
While talking about the octet rule, we do not think about $d$ or $f$ electrons. Just the $s$ and $p$ electrons are engaged with the octet rule, making it valuable for the primary gathering; an octet in these particles compares to electron designs finishing with ${s^2}{p^6}$. All atoms in the molecules have a total valence electron tally. When phosphorous frequently has five orbitals (ten electrons) and sulfur regularly has six orbitals (twelve electrons) since they are in the third time frame, yet nitrogen and oxygen can never have expanded octets since they are in the subsequent period and there is no such thing as a $2d$ orbital.
Note:
We have to know that the idea that mixtures containing carbon, nitrogen, oxygen, and fluorine are steadier if these particles have eight valence electrons. Each carbon, nitrogen, oxygen, and fluorine atom in this atom has a full octet.
Complete answer:
The octet rule is the understanding that most atoms seek to gain stability in their outermost energy level by filling the $s$ and $p$ orbitals of the highest energy level with eight electrons.
We have to know that the nitrogen has an electron configuration of $1{s^2}2{s^2}2{p^3}$ this means that nitrogen has five valence electrons $2{s^2}2{p^3}$. Nitrogen seeks out three additional electrons to fill the $p$ orbital and gain the stability of a noble gas, $1{s^2}2{s^2}2{p^6}$. However, now nitrogen has ten electrons and only seven protons making it a $ - 3$ charge anion ${N^{ - 3}}$.
Additional information:
While talking about the octet rule, we do not think about $d$ or $f$ electrons. Just the $s$ and $p$ electrons are engaged with the octet rule, making it valuable for the primary gathering; an octet in these particles compares to electron designs finishing with ${s^2}{p^6}$. All atoms in the molecules have a total valence electron tally. When phosphorous frequently has five orbitals (ten electrons) and sulfur regularly has six orbitals (twelve electrons) since they are in the third time frame, yet nitrogen and oxygen can never have expanded octets since they are in the subsequent period and there is no such thing as a $2d$ orbital.
Note:
We have to know that the idea that mixtures containing carbon, nitrogen, oxygen, and fluorine are steadier if these particles have eight valence electrons. Each carbon, nitrogen, oxygen, and fluorine atom in this atom has a full octet.
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