Question

What is $ {{200}^{o}}F $ in Celsius?

Answer 1

Hint :We know that by recalling the formula for conversion of Fahrenheit to Celsius. We can use $ 200 $ degrees as the temperature in Fahrenheit. Temperature in Celsius is equal to temperature in Fahrenheit minus $ 32, $ all multiplied by $ 5 $ over $ 9. $ The formula used here is $ {{T}_{C}}=\dfrac{5}{9}\left( {{T}_{F}}-32 \right) $ for conversion of Fahrenheit to Celsius.

Complete Step By Step Answer:
To solve the above, all that is required is to recall the conversion formula, and replace the temperature given in Fahrenheit given in the proper place. Generally, the temperature in degree Celsius is equal to the temperature in Fahrenheit minus $ 32 $ , all multiplied by $ 5 $ over $ 9. $ What is meant is that, the difference between ten degree Fahrenheit and zero degree Fahrenheit is not the same as the difference between ten degree Celsius and zero degree Celsius. The Fahrenheit scale increases faster. This is in contrast to kelvin and degree Celsius scales where the scale has the differences
This can be mathematically written as $ {{T}_{C}}=\dfrac{5}{9}\left( {{T}_{F}}-32 \right) $
Where, $ {{T}_{C}} $ is the temperature in degrees Celsius, and $ {{T}_{F}} $ is the temperature in Fahrenheit. Thus We are told to convert $ 200 $ degree Fahrenheit into Celsius. To do this we simply replace the number $ 200 $ with the variable $ {{T}_{F}} $ ;
Hence we have; $ {{T}_{C}}=\dfrac{5}{9}\left( 200-32 \right) $
 $ \Rightarrow {{T}_{C}}=\dfrac{5}{9}(168) $
 $ \Rightarrow {{T}_{C}}=\dfrac{850}{9}=93.33333 $
Therefore, we have the value; $ \Rightarrow {{T}_{C}}\approx 93.3 $ .

Note :
As seen, one should note that due to the factor $ 5 $ over $ 9. $ The temperature (or range of temperature) of a substance given in degree Fahrenheit has a totally different scale from that of the substance whose temperature (or range of temperature) is specified in degree Celsius.