
When water is heated from \[{0^o}C\], its volume,
A.Increases
B.Decreases till \[{4^o}C\]
C.Remains the same
D.First increase then decrease
Answer
490.2k+ views
Hint: We have to know that the water is an inorganic compound which does not have any taste and odor. And the water is a volatile liquid which is transparent in nature. The particles present in the liquid are far apart. Hence, it can easily move very easily due to the less intermolecular attraction between the particles. The water does not have any definite shape, but it has a definite volume. The shape will depend upon the container.
Complete answer:
When the water is heated from \[{0^o}C\], the volume of water will not increase first. Hence, option (A) is incorrect.
If the water is heated from \[{0^o}C\], volume will not decrease up to \[{4^o}C\]. Hence, option (B) is incorrect.
By the heating of water from \[{0^o}C\], the volume of water will not remain the same. Hence, option (C) is incorrect.
When the water is heated from \[{0^o}C\], the volume of water first decreases and then increases. The property of water is always unique in an anomalous expansion. When the water is heated from \[{0^o}C\], instead of expanding, the water will continuously contract. Which means, the volume of water is decreasing up to a particular temperature. And it will start to expand if again it is heated again. Therefore, we can say that the water is heated from\[{0^o}C\], the volume of water first decreases and then increases.
Hence, option (D) is correct.
Note:
We have to know that the water is made up of oxygen and hydrogen gases. And it is prepared by mixing two gases in the presence of sufficient heat. The water has a simple molecular structure which contains one oxygen atom and two hydrogen atoms. The water is a polar compound which is used as an excellent solvent. And the water has a high heat of vaporization and heat capacity.
Complete answer:
When the water is heated from \[{0^o}C\], the volume of water will not increase first. Hence, option (A) is incorrect.
If the water is heated from \[{0^o}C\], volume will not decrease up to \[{4^o}C\]. Hence, option (B) is incorrect.
By the heating of water from \[{0^o}C\], the volume of water will not remain the same. Hence, option (C) is incorrect.
When the water is heated from \[{0^o}C\], the volume of water first decreases and then increases. The property of water is always unique in an anomalous expansion. When the water is heated from \[{0^o}C\], instead of expanding, the water will continuously contract. Which means, the volume of water is decreasing up to a particular temperature. And it will start to expand if again it is heated again. Therefore, we can say that the water is heated from\[{0^o}C\], the volume of water first decreases and then increases.
Hence, option (D) is correct.
Note:
We have to know that the water is made up of oxygen and hydrogen gases. And it is prepared by mixing two gases in the presence of sufficient heat. The water has a simple molecular structure which contains one oxygen atom and two hydrogen atoms. The water is a polar compound which is used as an excellent solvent. And the water has a high heat of vaporization and heat capacity.
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