Answer
Verified
381.9k+ views
Hint: This question requires the knowledge of fluid mechanics. This problem is based upon the topic of velocity of efflux. The velocity of efflux is the velocity with which a liquid will come out of a hole carved at some height from the bottom of the container in which the liquid is filled.
Complete step by step answer:
Consider a liquid-filled tank (e.g. water tank). At some point in time, there should be a hole in the tank's wall at a depth h from the fluid's free surface in the open tank. The tank's cross section area, A, is much larger than the hole's cross section area, a. (A>>>a)
The efflux velocity, ${v_e}$, is the rate at which the fluid emerges from the hole.
Let ${v_e}$ be the velocity with which the fluid leaves. ${v_g}$, velocity at ground will be zero.
$g$ be acceleration due to gravity and $h$be the height from which fluid falls.
So according to equation of motion,
${v_g}^2 = {v_e}^2 + 2gh$
Since water is flowing downwards, we take $h$ as negative.
$0 = {v_e}^2 - 2gh$
${v_e} = \sqrt {2gh} $
This is the expression for velocity of efflux.
Note: The velocity of efflux is independent of the nature of liquid, quantity of liquid in the vessel and the area of orifice. More the height of the hole from the surface, more will be the velocity of efflux. The velocity of efflux of a liquid is the same as the speed an object would acquire while falling from the same height.
Complete step by step answer:
Consider a liquid-filled tank (e.g. water tank). At some point in time, there should be a hole in the tank's wall at a depth h from the fluid's free surface in the open tank. The tank's cross section area, A, is much larger than the hole's cross section area, a. (A>>>a)
The efflux velocity, ${v_e}$, is the rate at which the fluid emerges from the hole.
Let ${v_e}$ be the velocity with which the fluid leaves. ${v_g}$, velocity at ground will be zero.
$g$ be acceleration due to gravity and $h$be the height from which fluid falls.
So according to equation of motion,
${v_g}^2 = {v_e}^2 + 2gh$
Since water is flowing downwards, we take $h$ as negative.
$0 = {v_e}^2 - 2gh$
${v_e} = \sqrt {2gh} $
This is the expression for velocity of efflux.
Note: The velocity of efflux is independent of the nature of liquid, quantity of liquid in the vessel and the area of orifice. More the height of the hole from the surface, more will be the velocity of efflux. The velocity of efflux of a liquid is the same as the speed an object would acquire while falling from the same height.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The only snake that builds a nest is a Krait b King class 11 biology CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Why is there a time difference of about 5 hours between class 10 social science CBSE
Which places in India experience sunrise first and class 9 social science CBSE