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How many valence electrons does Fluorine have?

Last updated date: 17th Jun 2024
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Hint:In order to answer the number of valence electrons present in Fluorine, we must first know about the atomic number and electronic configuration of Fluorine. Fluorine is a chemical element which is represented by the chemical symbol ‘F’ and it will be having an atomic number of 9.

Complete answer:
Fluorine is a chemical element with an atomic number of 9 and it is represented by a chemical symbol of ‘F’. Fluorine is a very toxic gas with a pale yellow colour.
The electronic configuration of fluorine is given as \[1{s^2}2{s^2}2{p^5}\] which can also be written as \[[He]2{s^2}2{p^5}\]. From the electronic configuration, we can say that the number of valence electrons present in the Fluorine is 7. Fluorine will be having an oxidation number of -1.
Fluorine belongs to the p-block element and it is present in the group 17 and period 2 of the periodic table. It is the first member of the halogen family and is the most electronegative element present. Except with noble gases, fluorine is highly reactive with other elements present.
Therefore, the number of valence electrons in Fluorine is 7.

We have to remember that Fluorine though being a poisonous gas, it can have various uses. Some of the uses of Fluorine are given below:
- In order to prevent dental cavities, Fluorides are being added to the tooth pastes.
- Fluorine is used to prepare Teflon, which is used for making non-stick pans.
- The fluorine metals are used to detect any disorder present in the circulatory system.
- Both atomic and molecular fluorine have been used in the manufacture of semiconductors. It has been used for various purposes such as flat panel display product and plasma etching.