How do you use the binomial series to expand \[\dfrac{1}{{{\left( 2+x \right)}^{3}}}\]?
Answer
570k+ views
Hint: In this problem, we have to use the binomial series to expand the given expression. We know that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem. The binomial series formula is \[{{\left( a+b \right)}^{n}}={{a}^{n}}+n{{a}^{n-1}}b+\dfrac{n\left( n-1 \right)}{1\times 2}{{a}^{n-2}}{{b}^{2}}+\dfrac{n\left( n-1 \right)\left( n-2 \right)}{1\times 2\times 3}{{a}^{n-3}}{{b}^{3}}...\]. We can write the given expression in terms of the right-hand side of the binomial theorem and we can substitute the values, a, b. n in the binomial series formula to expand it.
Complete step by step answer:
We have to use the binomial theorem to expand \[\dfrac{1}{{{\left( 2+x \right)}^{3}}}\].
We know that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem.
We know that the binomial series is,
\[{{\left( a+b \right)}^{n}}={{a}^{n}}+n{{a}^{n-1}}b+\dfrac{n\left( n-1 \right)}{1\times 2}{{a}^{n-2}}{{b}^{2}}+\dfrac{n\left( n-1 \right)\left( n-2 \right)}{1\times 2\times 3}{{a}^{n-3}}{{b}^{3}}...\]
We can write the given expression as,
\[\Rightarrow \dfrac{1}{{{\left( 2+x \right)}^{-3}}}={{\left( 2+x \right)}^{-3}}\]
Here, a = 2, b = x, n = -3.
We can now expand the expression using binomial series, we get
\[\Rightarrow {{\left( 2+x \right)}^{-3}}={{2}^{-3}}+\left( -3 \right)\left( {{2}^{-4}} \right)x+\dfrac{-3\left( -4 \right)}{1\times 2}{{2}^{-5}}{{x}^{2}}+\dfrac{-3\left( -4 \right)\left( -5 \right)}{6}{{2}^{-6}}{{x}^{3}}...\]
We can now simplify the above step, we get
\[\Rightarrow \dfrac{1}{{{\left( 2+x \right)}^{3}}}=\dfrac{1}{8}-\dfrac{3}{16}x+\dfrac{3}{16}{{x}^{2}}-\dfrac{5}{32}{{x}^{3}}+...\]
Therefore, the expansion using binomial series is, \[\dfrac{1}{{{\left( 2+x \right)}^{3}}}=\dfrac{1}{8}-\dfrac{3}{16}x+\dfrac{3}{16}{{x}^{2}}-\dfrac{5}{32}{{x}^{3}}+...\].
Note: we should know that, any number with the negative power, can be written in a fraction form, by writing it in the denominator with the same power as positive. We should remember that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem.
Complete step by step answer:
We have to use the binomial theorem to expand \[\dfrac{1}{{{\left( 2+x \right)}^{3}}}\].
We know that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem.
We know that the binomial series is,
\[{{\left( a+b \right)}^{n}}={{a}^{n}}+n{{a}^{n-1}}b+\dfrac{n\left( n-1 \right)}{1\times 2}{{a}^{n-2}}{{b}^{2}}+\dfrac{n\left( n-1 \right)\left( n-2 \right)}{1\times 2\times 3}{{a}^{n-3}}{{b}^{3}}...\]
We can write the given expression as,
\[\Rightarrow \dfrac{1}{{{\left( 2+x \right)}^{-3}}}={{\left( 2+x \right)}^{-3}}\]
Here, a = 2, b = x, n = -3.
We can now expand the expression using binomial series, we get
\[\Rightarrow {{\left( 2+x \right)}^{-3}}={{2}^{-3}}+\left( -3 \right)\left( {{2}^{-4}} \right)x+\dfrac{-3\left( -4 \right)}{1\times 2}{{2}^{-5}}{{x}^{2}}+\dfrac{-3\left( -4 \right)\left( -5 \right)}{6}{{2}^{-6}}{{x}^{3}}...\]
We can now simplify the above step, we get
\[\Rightarrow \dfrac{1}{{{\left( 2+x \right)}^{3}}}=\dfrac{1}{8}-\dfrac{3}{16}x+\dfrac{3}{16}{{x}^{2}}-\dfrac{5}{32}{{x}^{3}}+...\]
Therefore, the expansion using binomial series is, \[\dfrac{1}{{{\left( 2+x \right)}^{3}}}=\dfrac{1}{8}-\dfrac{3}{16}x+\dfrac{3}{16}{{x}^{2}}-\dfrac{5}{32}{{x}^{3}}+...\].
Note: we should know that, any number with the negative power, can be written in a fraction form, by writing it in the denominator with the same power as positive. We should remember that the binomial series is a kind of formula that helps us to expand binomials raised to the power of any number using the binomial theorem.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

How many of the following diseases can be studied with class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Which of the following enzymes is used for carboxylation class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

