Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

Upon heating KClO3 in the presence of catalysis amount of MnO2, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure HNO3 gives Y and Z.
(a) W and X are respectively
      A. O2 and P4O10
      B. O2 and P4O6
      C. O3 and P4O6
      D. O3 and P4O10
(b) Y and Z are respectively
       A. N2O5 and HPO3
       B. N2O4 and HPO3
       C. N2O4 and H3PO3
       D. N2O3 and H3PO4

Answer
VerifiedVerified
495.9k+ views
like imagedislike image
Hint: The given questions can be solved by understanding the nitrogen and oxygen family properly since phosphorus comes under the nitrogen family. MnO2 acts as an oxidizing agent and reducing agent.

Complete step by step solution:
The given question can be expressed as given below:
3KClO3MnO2ΔW5O2+P4ΔXP4O10HNO3Y+Z
We have to find the compounds W, X, Y, and Z.
When KClO3 is heated in the presence of a catalyst, MnO2, oxygen gas is formed. The reaction is given below:
3KClO3+MnO2Δ3O2+3KCl
Thus the compound W is oxygen gas, O2.
Next step is the reaction of an excess amount of W with white phosphorus, i.e. P4.
i.e. 3O2P4P4O10
Now we have obtained the compound X, i.e. X is P4O10.
Now we have to react to the compound X with pure nitric acid, HNO3 to give Y and Z. The corresponding reaction is given below:
P4O10HNO3HPO3+N2O5
Thus the compounds Y and Z are obtained. Y is H3PO3 and Z is N2O5.
Altogether, the complete chemical balanced equation can be represented as given below:
3KClO3catalystMnO23O2+3KClP4P4O10HNO3HPO3+N2O5
Thus the compounds W, X, Y and Z are O2,P4O10,N2O5,HPO3 respectively.
(a) W and X are O2,P4O10 respectively.
Hence the correct option is A.

(b) Y and Z are N2O5 and HPO3 respectively.

Hence the correct option is A.

Additional information:
The amount of oxygen reacted with white phosphorus can differ the products formed. If the amount of oxygen gas is less, P4O6 is formed. When the amount is excess, the product formed will be P4O10 .

Note: When we come across this type of reaction, it is important to write and balance the chemical equation. Such reactions require energy sources like heat, light or electricity which helps to break the bonds between them. The reaction of heating potassium chlorate is an example of decomposition reaction.
Latest Vedantu courses for you
Grade 9 | CBSE | SCHOOL | English
Vedantu 9 CBSE Pro Course - (2025-26)
calendar iconAcademic year 2025-26
language iconENGLISH
book iconUnlimited access till final school exam
tick
School Full course for CBSE students
PhysicsPhysics
Social scienceSocial science
BiologyBiology
ChemistryChemistry
EnglishEnglish
MathsMaths
₹41,000 (9% Off)
₹37,300 per year
Select and buy