
Two dice are thrown simultaneously. Find the probability of getting: a multiple of 2 on one dice and a multiple of 3 on other.
Answer
600.3k+ views
Hint: First we have to find the probability of individual events. Then, we have to evaluate the sample space of the particular event and then find the favorable outcome from the sample set and finally evaluate the probability.
Complete step-by-step answer:
If a random experiment is performed, then each of its outcomes is known as an elementary event.
The set of all possible outcomes of a random experiment is called the sample space associated with it and it is generally denoted by ‘S’.
For an event of throwing of single die, sample space of die is given as:
\[s\text{ }=\text{ }\left\{ 1,\text{ }2,\text{ }3,\text{ }4,\text{ }5,\text{ }6 \right\}.\]
Similarly, for an event of two dice thrown simultaneously, sample space of two dice are given as:
$\begin{align}
& S=\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6), \\
& \text{ }(2,1),(2,2),(2,3),(2,4),(2,5),(2,6), \\
& \text{ }(3,1),(3,2),(3,3),(3,4),(3,5),(3,6), \\
& \text{ }(4,1),(4,2),(4,3),(4,4),(4,5),(4,6), \\
& \text{ }(5,1),(5,2),(5,3),(5,4),(5,5),(5,6), \\
& \text{ }(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\} \\
\end{align}$
The space of the multiple of 2 on one dice and a multiple of 3 on other dice is given as:
$E=\{(2,3),(2,6),(4,3),(4,6),(6,3),(6,6)\}$
So, now the probability of the given event(E) can be shown as:
\[P(E)=\dfrac{(Number\text{ of favorable outcomes)}}{(T\text{otal number of possible outcomes)}}\]
Therefore, the number of favorable outcomes in the sample space = 6.
Total number of possible outcomes of sample space = 36.
The probability of the given event is:
P (Getting multiple of 2 on one dice and multiple of 3 on other dice)$=\dfrac{6}{36}$
P (Getting multiple of 2 on one dice and multiple of 3 on other dice)$=\dfrac{1}{6}.$
$\therefore $The probability of getting multiple of 2 on one dice and multiple of 3 on other dice is $\dfrac{1}{6}.$
Note: Focus must be emphasized on finding the sample space and favorable outcomes particularly for probability related problems. After this the problem is reduced to mathematical calculations only.
Complete step-by-step answer:
If a random experiment is performed, then each of its outcomes is known as an elementary event.
The set of all possible outcomes of a random experiment is called the sample space associated with it and it is generally denoted by ‘S’.
For an event of throwing of single die, sample space of die is given as:
\[s\text{ }=\text{ }\left\{ 1,\text{ }2,\text{ }3,\text{ }4,\text{ }5,\text{ }6 \right\}.\]
Similarly, for an event of two dice thrown simultaneously, sample space of two dice are given as:
$\begin{align}
& S=\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6), \\
& \text{ }(2,1),(2,2),(2,3),(2,4),(2,5),(2,6), \\
& \text{ }(3,1),(3,2),(3,3),(3,4),(3,5),(3,6), \\
& \text{ }(4,1),(4,2),(4,3),(4,4),(4,5),(4,6), \\
& \text{ }(5,1),(5,2),(5,3),(5,4),(5,5),(5,6), \\
& \text{ }(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\} \\
\end{align}$
The space of the multiple of 2 on one dice and a multiple of 3 on other dice is given as:
$E=\{(2,3),(2,6),(4,3),(4,6),(6,3),(6,6)\}$
So, now the probability of the given event(E) can be shown as:
\[P(E)=\dfrac{(Number\text{ of favorable outcomes)}}{(T\text{otal number of possible outcomes)}}\]
Therefore, the number of favorable outcomes in the sample space = 6.
Total number of possible outcomes of sample space = 36.
The probability of the given event is:
P (Getting multiple of 2 on one dice and multiple of 3 on other dice)$=\dfrac{6}{36}$
P (Getting multiple of 2 on one dice and multiple of 3 on other dice)$=\dfrac{1}{6}.$
$\therefore $The probability of getting multiple of 2 on one dice and multiple of 3 on other dice is $\dfrac{1}{6}.$
Note: Focus must be emphasized on finding the sample space and favorable outcomes particularly for probability related problems. After this the problem is reduced to mathematical calculations only.
Recently Updated Pages
Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Computer Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

The draft of the Preamble of the Indian Constitution class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

How many members did the Constituent Assembly of India class 10 social science CBSE

Write an application to the principal requesting five class 10 english CBSE

The Constitution of India was adopted on A 26 November class 10 social science CBSE

