Question

Two bulbs, one of $50$ watt and another of \[25\] watt are connected in series to the mains. Find the ratio of currents through them.

Answer 1

Hint: When the same current passes through all of the components in a circuit, it is said to be connected in series. The current in such circuits has only one route. Consider a series circuit as a set of decorative string lights for the home. This is nothing more than a string of small lights connected in a series. If one bulb in a series burns out, the rest of the bulbs in the series will not light up.

Complete step by step solution:
As the power given is given for both lamps in series. We can calculate the current from power by formula $I = \sqrt {\dfrac{P}{R}} $ .

The same amount of current runs across all parts in a series configuration.
Because the bulbs are connected in series, the current flowing through them will be the same. When resistors are connected in a series circuit, the voltage across each resistor varies, despite the fact that the current flow through all of them is the same.
The ratio of current through the above given bulbs will be $1:1$ .
Therefore, the answer will be \[1:1\] .

Note: All components in a series circuit are connected end-to-end, forming a single current flow route. All components in a parallel circuit are linked across each other, forming two sets of electrically common points. In a parallel circuit, a "branch" is an electric current path formed by one of the load components (such as a resistor).