Question

Total number of $\sigma $bonds in ${{N}_ {3}}H$is _______

Answer 1

Hint: Hydrazoic acid, also known as hydrogen azide or azoimide, is a compound with the chemical formula ${{N}_ {3}}H$. It is a colourless, volatile, and explosive liquid at room temperature and pressure. It is a compound of nitrogen and hydrogen, and is therefore a pnictogen hydride.

Complete step by step solution:
We have been provided with a compound ${{N}_ {3}}H$,
Its IUPAC name Hydrogen azide is a nitrogen hydride. It is a conjugate acid of an azide anion,
The hybridisation of the central N atom is only $sp$. And, remaining two N atoms is $s{{p}^ {2}} $
Its structure is:

Sigma bonds are the strongest type of covalent chemical bond. They are formed by head-on overlapping between atomic orbitals. Sigma bonding is most simply defined for diatomic molecules using the language and tools of symmetry groups.
Pi bonds are covalent chemical bonds where two lobes of an orbital on one atom overlap two lobes of an orbital on another atom and this overlap occurs laterally. Each of these atomic orbitals has zero electron density at a shared nodal plane, passing through the two bonded nuclei.

From this we came to know that Hydrazoic acid has 3 sigma bonds with 3 hydrogens and zero pi bonds and has a lone pair of electrons.

Note: ${{N}_ {3}}H$ is called the covalent azide and it does not dissociate easily. This makes sodium azide more stable than hydrazoic acid. Hence, $N{{a}^ {+}} {{N}^ {3-}} $decomposes at a much higher temperature than ${{N}_ {3}}H$and hence, the higher thermal stability of $N{{H}_ {3}} Na$.