
There is a narrow rectangular plot, reserved for a school, in Mahuli village. The length and breadth of the plot are in the ratio 11:4. At the rate of Rs. 100 per metre it will cost the village panchayat Rs. 75000 to fence the plot. What are the dimensions of the plot?
A. Length = 160m and Breadth = 80m
B. Length = 275m and Breadth = 100m
C. Length = 260m and Breadth = 120m
D. Length = 235m and Breadth = 90m
Answer
606.3k+ views
Hint: We will divide the total cost of the fencing by the rate per metre, which is 100, and get the perimeter of the plot. We know the perimeter of a rectangle is given by 2(l + b), so using this formula we can find the dimensions of the plot.
Complete step-by-step answer:
It is given in the question that Mahuli village has a rectangular plot that is reserved for the school. Also, the ratio of the length and breadth of the plot is given as 11:4, the rate of fencing per metre is Rs. 100 and the total amount paid by the village panchayat for fencing the entire plot is Rs. 75000. We have to find the dimensions of the plot. So, from the question, we get the ratio of the plot as,
$\dfrac{\text{Length}}{\text{Breadth}}=\dfrac{11}{4}$
Now, we will try to find the perimeter of the rectangle from the total cost of fencing paid by the panchayat. So, the total perimeter of the plot is given as,
$\dfrac{\text{Total cost of fencing}}{\text{Cost of 1m of fencing}}$
$\begin{align}
& =\dfrac{75000}{100} \\
& \Rightarrow 750m \\
\end{align}$
Thus, the perimeter of the plot for the school in the village is of 750m. We know that the perimeter of a rectangle is given by 2(l + b) and we have the perimeter of the rectangle as 750m. So,
2(l + b) = 750
But the length and breadth are in the ratio of 11:4, so equating them, we get,
$ \Rightarrow 2\left( 11x+4x \right)=750$
$ \Rightarrow 2\left( 15x \right)=750$
$ \Rightarrow 30x=750$
$ \Rightarrow x=\dfrac{750}{30}$
$ \Rightarrow x=25$
So, we get the length of the rectangular plot as $11\times 25=275m$. Similarly, we get the breadth as $4\times 25=100m$.
Therefore, we get the length of the rectangular plot as 275m and the breadth as 100m, so the correct answer is option B.
Note: In this type of questions, always use the derived formulas of polygons, like the perimeter of rectangle = 2(l + b), area of rectangle $=l\times b$, etc.
For example, if ABCD is a rectangle, then the perimeter of this rectangle is given as the length of its sides, which is (AB + BC + CD + DA) or (l + b + l + b) which is equal to 2(l + b). Thus, the perimeter of the rectangle is 2(l + b).
Complete step-by-step answer:
It is given in the question that Mahuli village has a rectangular plot that is reserved for the school. Also, the ratio of the length and breadth of the plot is given as 11:4, the rate of fencing per metre is Rs. 100 and the total amount paid by the village panchayat for fencing the entire plot is Rs. 75000. We have to find the dimensions of the plot. So, from the question, we get the ratio of the plot as,
$\dfrac{\text{Length}}{\text{Breadth}}=\dfrac{11}{4}$
Now, we will try to find the perimeter of the rectangle from the total cost of fencing paid by the panchayat. So, the total perimeter of the plot is given as,
$\dfrac{\text{Total cost of fencing}}{\text{Cost of 1m of fencing}}$
$\begin{align}
& =\dfrac{75000}{100} \\
& \Rightarrow 750m \\
\end{align}$
Thus, the perimeter of the plot for the school in the village is of 750m. We know that the perimeter of a rectangle is given by 2(l + b) and we have the perimeter of the rectangle as 750m. So,
2(l + b) = 750
But the length and breadth are in the ratio of 11:4, so equating them, we get,
$ \Rightarrow 2\left( 11x+4x \right)=750$
$ \Rightarrow 2\left( 15x \right)=750$
$ \Rightarrow 30x=750$
$ \Rightarrow x=\dfrac{750}{30}$
$ \Rightarrow x=25$
So, we get the length of the rectangular plot as $11\times 25=275m$. Similarly, we get the breadth as $4\times 25=100m$.
Therefore, we get the length of the rectangular plot as 275m and the breadth as 100m, so the correct answer is option B.
Note: In this type of questions, always use the derived formulas of polygons, like the perimeter of rectangle = 2(l + b), area of rectangle $=l\times b$, etc.
For example, if ABCD is a rectangle, then the perimeter of this rectangle is given as the length of its sides, which is (AB + BC + CD + DA) or (l + b + l + b) which is equal to 2(l + b). Thus, the perimeter of the rectangle is 2(l + b).
Recently Updated Pages
What happens to glucose which enters nephron along class 10 biology CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

When the JanmiKudian Act was passed that granted the class 10 social science CBSE

A sector containing an angle of 120 circ is cut off class 10 maths CBSE

The sum of digits of a two digit number is 13 If t-class-10-maths-ICSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

Discuss the main reasons for poverty in India

