Question

There are two types of packing of candies. Each mega (large type) has 20 more candies than the no. of candies in 15 packs of smaller type. If each mega type contains 200 candies find the no. of candies in each small box.

Answer 1

Hint: Let the number of candies in small box be x. As given that the mega box has 20 more candies than the no. of candies in 15 packs of smaller type. And we also know the total number of candies are 200 Hence, we can form the linear equation and can solve the above equation.

Complete step-by-step answer:
As given that the mega box has 20 more candies than the no. of candies in 15 packs of smaller type. And we also know the total number of candies are 200.
So, let the number of candies in small box be x
So, candies in one mega box is 20 more candies than the no. of candies in 15 packs of smaller type.
Hence, it is \[15x + 20\]
And the total number of candies are 200.so,
\[ \Rightarrow \]\[15x + 20 = 200\]
On simplification we get,
\[ \Rightarrow \]\[15x = 200 - 20 = 180\]
On solving for x,
\[ \Rightarrow \]\[x = \dfrac{{180}}{{15}}\]
On dividing we get,
\[x = 12\]
Hence, there are 12 candies in one small pack.

Note: Form the linear equation by assuming the unknown number of smaller packs and calculate the equation properly.
Hence, use of unknown numbers can be seen clearly in the above questions as by forming the equation from all the given values.
And the one equation and one variable can be calculated.
If there are many equations in one variable we can check the credibility of our solution by substituting the value of the variable in other equations, if it satisfies, then we have got our answer, if it doesn’t satisfy then the equation has no solution.