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The volume of CO2 obtained at STP by the complete decomposition of 9.85 g Na2CO3 is:
(A) 2.25 litre
(B) zero
(C) 0.85 litre
(D) 0.56 litre

Answer
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Hint: The sodium carbonate will produce from the decomposition of sodium bicarbonate. The chemical formula of sodium carbonate is Na2CO3 and is named as washing soda. When this sodium carbonate is heated it undergoes a thermal decomposition reaction.

Complete answer:
To calculate the number of moles of sodium carbonate,
number of moles of Na2CO3=given mass of Na2CO3molar mass of Na2CO3 
Given the mass of sodium carbonate = 9.58g
Molar mass of sodium carbonate (Na2CO3=2XNa+1XC+3XO=2X23+1X12+3X16 ) =106 g/mol
Substitute these values in the above equation of the number of moles of sodium carbonate,
number of moles of Na2CO3=given mass of Na2CO3molar mass of Na2CO3 =9.58g106g/mole=0.093mol
The thermal decomposition of sodium carbonate will take place above 500oC . the reaction of decomposition is:
     Na2CO3(s)Na2O(s)+CO2(g)
(The name of the first reaction product is sodium oxide which is a solid and used in glassmaking and the name of the second product is carbon dioxide which is a gas)
By Stoichiometric of the above reaction:
1 mole of sodium carbonate produces 1 mole of carbon dioxide.
So, 0.093 moles of sodium carbonate will produce = 0.093 moles of carbon dioxide
At STP:
1 mole of a gas occupies 22.4 L of volume.
So, 0.093 moles of carbon dioxide will occupy = 0.093X22.4=2.08 L of carbon dioxide.
But, sodium carbonate is soda ash and it does not decompose at STP conditions. Hence carbon dioxide does not involve.

So, the correct answer is Zero liters. Option B

Note:
STP means Standard Temperature and Pressure, which denotes the same temperature of 0oC (273.15K), but a slightly high pressure of 1 atm (101.325kPa). These values approximate the freezing temperature of the water and atmospheric pressure at sea level. One mole of any of a combination of gases occupies 22.4 L of volume at STP.
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