Question

The volume of $C{{O}_{2}}$ obtained at STP by the complete decomposition of 9.85 g $N{{a}_{2}}C{{O}_{3}}$ is:
(A) 2.25 litre
(B) zero
(C) 0.85 litre
(D) 0.56 litre

Answer 1

Hint: The sodium carbonate will produce from the decomposition of sodium bicarbonate. The chemical formula of sodium carbonate is $N{{a}_{2}}C{{O}_{3}}$ and is named as washing soda. When this sodium carbonate is heated it undergoes a thermal decomposition reaction.

Complete answer:
To calculate the number of moles of sodium carbonate,
\[number\text{ }of\text{ }moles\text{ }of\text{ }N{{a}_{2}}\text{C}{{\text{O}}_{3}}\text{=}\dfrac{given\text{ }mass\text{ }of\text{ }N{{a}_{2}}\text{C}{{\text{O}}_{3}}}{\text{molar }mass\text{ }of\text{ }N{{a}_{2}}\text{C}{{\text{O}}_{3}}}\text{ }\]
Given the mass of sodium carbonate = 9.58g
Molar mass of sodium carbonate ($N{{a}_{2}}C{{O}_{3}}=2XNa+1XC+3XO=2X23+1X12+3X16$ ) =106 g/mol
Substitute these values in the above equation of the number of moles of sodium carbonate,
\[number\text{ }of\text{ }moles\text{ }of\text{ }N{{a}_{2}}\text{C}{{\text{O}}_{3}}\text{=}\dfrac{given\text{ }mass\text{ }of\text{ }N{{a}_{2}}\text{C}{{\text{O}}_{3}}}{\text{molar }mass\text{ }of\text{ }N{{a}_{2}}\text{C}{{\text{O}}_{3}}}\text{ =}\dfrac{9.58g}{106g/mole}=0.093mol\]
The thermal decomposition of sodium carbonate will take place above ${{500}^{o}}C$ . the reaction of decomposition is:
     \[N{{a}_{2}}C{{O}_{3}}(s)\to N{{a}_{2}}O(s)+C{{O}_{2}}(g)\]
(The name of the first reaction product is sodium oxide which is a solid and used in glassmaking and the name of the second product is carbon dioxide which is a gas)
By Stoichiometric of the above reaction:
1 mole of sodium carbonate produces 1 mole of carbon dioxide.
So, 0.093 moles of sodium carbonate will produce = 0.093 moles of carbon dioxide
At STP:
1 mole of a gas occupies 22.4 L of volume.
So, 0.093 moles of carbon dioxide will occupy = 0.093X22.4=2.08 L of carbon dioxide.
But, sodium carbonate is soda ash and it does not decompose at STP conditions. Hence carbon dioxide does not involve.

So, the correct answer is Zero liters. Option B

Note:
STP means Standard Temperature and Pressure, which denotes the same temperature of ${{0}^{o}}C$ (273.15K), but a slightly high pressure of 1 atm (101.325kPa). These values approximate the freezing temperature of the water and atmospheric pressure at sea level. One mole of any of a combination of gases occupies 22.4 L of volume at STP.