
The velocity of light in diamond is $121000km.{{s}^{-1}}$. What is the refractive index?
A.)$1.47$
B.)$2.47$
C.)$3.52$
D.)$3.86$
Answer
581.4k+ views
Hint: The refractive index of a medium is a measure of the speed of light in the medium. In a medium with a higher refractive index (optically denser), light travels slower than that in a medium of lower refractive index (optically rarer). It can also be written as the ratio of the speed of light in vacuum (or air) to the speed of light in that medium.
Formula used: The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Complete step by step answer:
We will solve this problem by using the formula for the refractive index of a medium and plugging in the information given in the question. Hence, let us proceed to do that.
The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$ -(1)
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Now, let the speed of light in diamond be $v=121000km.{{s}^{-1}}=121000\times {{10}^{3}}m.{{s}^{-1}}=1.21\times {{10}^{8}}m.{{s}^{-1}}$ $\left( \because 1km.{{s}^{-1}}={{10}^{3}}m.{{s}^{-1}} \right)$
Let the refractive index of diamond be $n$.
Putting this information in (1), we get,
$n=\dfrac{3\times {{10}^{8}}}{1.21\times {{10}^{8}}}=\dfrac{3}{1.21}\approx 2.47$
Hence, the refractive index of diamond is $2.47$.
Therefore, the correct option is B) $2.47$.
Note: Students sometimes get confused in the ratio for the formula for the refractive index of a medium. A good way to remember is that theoretically nothing and travel faster than the speed of light and the refractive index of a medium cannot be greater than one in general. Hence, the speed of light in the ratio must be in the numerator so that the ratio (or the refractive index of the medium) comes out to be greater than one.
Formula used: The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Complete step by step answer:
We will solve this problem by using the formula for the refractive index of a medium and plugging in the information given in the question. Hence, let us proceed to do that.
The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$ -(1)
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Now, let the speed of light in diamond be $v=121000km.{{s}^{-1}}=121000\times {{10}^{3}}m.{{s}^{-1}}=1.21\times {{10}^{8}}m.{{s}^{-1}}$ $\left( \because 1km.{{s}^{-1}}={{10}^{3}}m.{{s}^{-1}} \right)$
Let the refractive index of diamond be $n$.
Putting this information in (1), we get,
$n=\dfrac{3\times {{10}^{8}}}{1.21\times {{10}^{8}}}=\dfrac{3}{1.21}\approx 2.47$
Hence, the refractive index of diamond is $2.47$.
Therefore, the correct option is B) $2.47$.
Note: Students sometimes get confused in the ratio for the formula for the refractive index of a medium. A good way to remember is that theoretically nothing and travel faster than the speed of light and the refractive index of a medium cannot be greater than one in general. Hence, the speed of light in the ratio must be in the numerator so that the ratio (or the refractive index of the medium) comes out to be greater than one.
Recently Updated Pages
Why is there a time difference of about 5 hours between class 10 social science CBSE

In cricket, what is a "pink ball" primarily used for?

In cricket, what is the "new ball" phase?

In cricket, what is a "death over"?

What is the "Powerplay" in T20 cricket?

In cricket, what is a "super over"?

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

