# The values of k for which the roots are real and equal of the following equation $k{x^2} - 2\sqrt 5 x + 4 = 0$ is $k = \dfrac{5}{4}$ .

(a) True

(b) False

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**Hint:**For the real and equal roots we know that the discriminant is equal to $0$ or for the equation $a{x^2} + bx + c = 0$ the condition for real and equal is ${b^2} - 4ac = 0$ from this concept we can solve this question easily.

**Complete step-by-step answer:**

We know that the condition for real and equal roots Discriminant = $0$ .

If equation is $a{x^2} + bx + c = 0$ then Discriminant is = ${b^2} - 4ac$ ;

Now compare the both equation for getting the values of $a,b,c$ :

$k{x^2} - 2\sqrt 5 x + 4 = 0$ with $a{x^2} + bx + c = 0$ ;

By comparing we get

$a = k$ , $b = - 2\sqrt 5 $ , $c = 4$

Now Discriminant of required equation is

${b^2} - 4ac$ = ${\left( { - 2\sqrt 5 } \right)^2} - 4 \times k \times 4 = 0$

By solving we get

$20 - 16k = 0$ ,

Now by rearranging we get,

$k = \dfrac{{20}}{{16}}$

Dividing Numerator or denominator by $4$ we get ,

$k = \dfrac{5}{4}$

Hence the value given is correct.

**So, the correct answer is “True”.**

**Note:**If in case we have to find the value of $k$ for two real and unequal roots then we have to do that Discriminant $ > 0$ or ${b^2} - 4ac$$ > 0$ .If in case we have to find the value of $k$ for imaginary roots then we have to do that Discriminant $ < 0$ or ${b^2} - 4ac$$ < 0$.When the Discriminant is negative then we get the pair of complex equations .If one root is given $a + ib$ than other will be the $a - ib$ .