# The value of x here is,$\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}+\text{xHCl}\to 2\text{NaCl + C}{{\text{O}}_{\text{2}}}\text{ + }{{\text{H}}_{\text{2}}}\text{O}$.

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Hint: Sodium bicarbonate reacts with hydrochloric acid to form sodium chloride, water and carbon dioxide as the products and this reaction takes place stoichiometrically depending upon the number of atoms present in the molecules of the reactants involved.

$\text{N}{{\text{a}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}+2\text{HCl}\to 2\text{NaCl + C}{{\text{O}}_{\text{2}}}\text{ + }{{\text{H}}_{\text{2}}}\text{O}$