
The two monomers for the synthesis of Nylon 6, 6 are:
(a)- $HOOC{{(C{{H}_{2}})}_{6}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$
(b)- $HOOC{{(C{{H}_{2}})}_{6}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{4}}N{{H}_{2}}$
(c)- $HOOC{{(C{{H}_{2}})}_{6}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{4}}N{{H}_{2}}$
(d)- $HOOC{{(C{{H}_{2}})}_{4}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$
Answer
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Hint: Nylon 6,6 is a polymer that is formed by condensation polymerization. It is made up of two monomers. The 6,6 in Nylon 6,6 indicates that both the monomers of Nylon 6,6 have 6 carbon atoms each.
Complete step by step answer:
Nylon 6,6 is a polymer. It comes under the polymers which have amide linkage. Amide linkage is formed between the carboxyl group of one molecule and the ammonia group of another molecule. The linkage is $-NH-CO-$. The linkage is caused by the elimination of a water molecule.
Nylon 6,6 is a polyamide. It comes under condensation polymerization because there is a loss of water molecules during the polymerization. There are two monomers in Nylon 6,6. These monomers are adipic acid and hexamethylenediamine. The formula of adipic acid is $HOOC{{(C{{H}_{2}})}_{4}}COOH$. It is made up of 6 carbon atoms. Each terminal is a carboxylic group. The formula of hexamethylenediamine is $\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$. It is also a 6 carbon atom molecule. Each terminal carbon atom is attached to the amine group.
The acid and the amine are heated at 525 K under pressure and undergo polymerization with the elimination of water as steam, nylon 6,6 is produced. The reaction of formation of Nylon 6,6 is given below:
Since both the monomers have 6 carbon atoms each, therefore, it is written as Nylon 6,6.
So, the correct answer is - $HOOC{{(C{{H}_{2}})}_{4}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$.
So, the correct answer is “Option D”.
Note: There are two more Nylon produced by condensation reaction:
(i)- Nylon 6,10, whose monomers are sebacic acid $HOOC{{(C{{H}_{2}})}_{8}}COOH$ and hexamethylenediamine $\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$
(ii)- Nylon 6, whose monomer is 6-Aminohexanoic acid ${{H}_{3}}{{N}^{+}}-{{(C{{H}_{2}})}_{5}}-CO{{O}^{-}}$.
Complete step by step answer:
Nylon 6,6 is a polymer. It comes under the polymers which have amide linkage. Amide linkage is formed between the carboxyl group of one molecule and the ammonia group of another molecule. The linkage is $-NH-CO-$. The linkage is caused by the elimination of a water molecule.
Nylon 6,6 is a polyamide. It comes under condensation polymerization because there is a loss of water molecules during the polymerization. There are two monomers in Nylon 6,6. These monomers are adipic acid and hexamethylenediamine. The formula of adipic acid is $HOOC{{(C{{H}_{2}})}_{4}}COOH$. It is made up of 6 carbon atoms. Each terminal is a carboxylic group. The formula of hexamethylenediamine is $\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$. It is also a 6 carbon atom molecule. Each terminal carbon atom is attached to the amine group.
The acid and the amine are heated at 525 K under pressure and undergo polymerization with the elimination of water as steam, nylon 6,6 is produced. The reaction of formation of Nylon 6,6 is given below:
Since both the monomers have 6 carbon atoms each, therefore, it is written as Nylon 6,6.
So, the correct answer is - $HOOC{{(C{{H}_{2}})}_{4}}COOH,\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$.
So, the correct answer is “Option D”.
Note: There are two more Nylon produced by condensation reaction:
(i)- Nylon 6,10, whose monomers are sebacic acid $HOOC{{(C{{H}_{2}})}_{8}}COOH$ and hexamethylenediamine $\text{ }{{H}_{2}}N{{(C{{H}_{2}})}_{6}}N{{H}_{2}}$
(ii)- Nylon 6, whose monomer is 6-Aminohexanoic acid ${{H}_{3}}{{N}^{+}}-{{(C{{H}_{2}})}_{5}}-CO{{O}^{-}}$.
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