
The transformed equation of ${x^4} + 8{x^3} + x - 5 = 0$ by eliminating second term is
(A) ${x^4} - 24{x^2} + 65x - 55 = 0$
(B) ${x^4} + 24{x^2} + 65x + 55 = 0$
(C) ${x^4} - 24{x^2} - 65x + 55 = 0$
(D) ${x^4} + 24{x^2} + 65x - 55 = 0$
Answer
578.7k+ views
Hint: At first use the substitution \[\left( {x + h} \right)\] in the place of x in the given equation. Now note that, in order to eliminate the second term from this transformed equation, the coefficient of \[{x^3}\] must be zero. Therefore find h and rewrite the transformed equation substituting the value of h.
Complete step by step answer:
According to the question we are to eliminate the second term from the equation ${x^4} + 8{x^3} + x - 5 = 0$..... (1)
Let us at first use the substitution \[\left( {x + h} \right)\] in the place of x in equation (1).
Therefore we have,
${\left( {x + h} \right)^4} + 8{\left( {x + h} \right)^3} + \left( {x + h} \right) - 5 = 0$
On expanding we get,
$ \Rightarrow {x^4} + 4{x^3}h + 6{x^2}{h^2} + 4x{h^3} + {h^4} + 8\left[ {{x^3} + 3{x^2}h + 3x{h^2} + {h^3}} \right] + x + h - 5 = 0$
On taking terms common we get,
$ \Rightarrow {x^4} + \left( {4h + 8} \right){x^3} + \left( {6{h^2} + 24h} \right){x^2} + \left( {4{h^3} + 24{h^2} + 1} \right)x + \left( {{h^4} + 8{h^3} + h - 5} \right) = 0$ ..... (2)
Now, in order to eliminate the second term from this transformed equation of${x^4} + 8{x^3} + x - 5 = 0$, we have to make the coefficient of \[{x^3}\] zero.
$ \Rightarrow 4h + 8 = 0$
On cross multiplication and simplification we get,
$ \Rightarrow h = \dfrac{{ - 8}}{4} = - 2$
Now, putting h=−2 in (2) we get,
$ \Rightarrow {x^4} + \left( { - 8 + 8} \right){x^3} + \left( {24 - 48} \right){x^2} + \left( { - 32 + 96 + 1} \right)x + \left( {16 - 64 - 2 - 5} \right) = 0$
On simplification we get,
$ \Rightarrow {x^4} - 24{x^2} + 65x - 55 = 0$
Therefore, the transformed equation of ${x^4} + 8{x^3} + x - 5 = 0$ by eliminating second term is ${x^4} - 24{x^2} + 65x - 55 = 0$
Hence, option (A) is correct.
Note: In mathematics, a polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables. An example of a polynomial of a single indeterminate x is \[{x^2}\; - {\text{ }}4x{\text{ }} + {\text{ }}7\]. Here, we have to eliminate second term so we take coefficient of \[{x^3}\] to be zero, in other questions if it is asked to eliminate any other term we first substitute \[\left( {x + h} \right)\] in place of x, and then take the coefficient of the term which is asked to eliminate, as 0, and then we solve further.
Complete step by step answer:
According to the question we are to eliminate the second term from the equation ${x^4} + 8{x^3} + x - 5 = 0$..... (1)
Let us at first use the substitution \[\left( {x + h} \right)\] in the place of x in equation (1).
Therefore we have,
${\left( {x + h} \right)^4} + 8{\left( {x + h} \right)^3} + \left( {x + h} \right) - 5 = 0$
On expanding we get,
$ \Rightarrow {x^4} + 4{x^3}h + 6{x^2}{h^2} + 4x{h^3} + {h^4} + 8\left[ {{x^3} + 3{x^2}h + 3x{h^2} + {h^3}} \right] + x + h - 5 = 0$
On taking terms common we get,
$ \Rightarrow {x^4} + \left( {4h + 8} \right){x^3} + \left( {6{h^2} + 24h} \right){x^2} + \left( {4{h^3} + 24{h^2} + 1} \right)x + \left( {{h^4} + 8{h^3} + h - 5} \right) = 0$ ..... (2)
Now, in order to eliminate the second term from this transformed equation of${x^4} + 8{x^3} + x - 5 = 0$, we have to make the coefficient of \[{x^3}\] zero.
$ \Rightarrow 4h + 8 = 0$
On cross multiplication and simplification we get,
$ \Rightarrow h = \dfrac{{ - 8}}{4} = - 2$
Now, putting h=−2 in (2) we get,
$ \Rightarrow {x^4} + \left( { - 8 + 8} \right){x^3} + \left( {24 - 48} \right){x^2} + \left( { - 32 + 96 + 1} \right)x + \left( {16 - 64 - 2 - 5} \right) = 0$
On simplification we get,
$ \Rightarrow {x^4} - 24{x^2} + 65x - 55 = 0$
Therefore, the transformed equation of ${x^4} + 8{x^3} + x - 5 = 0$ by eliminating second term is ${x^4} - 24{x^2} + 65x - 55 = 0$
Hence, option (A) is correct.
Note: In mathematics, a polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables. An example of a polynomial of a single indeterminate x is \[{x^2}\; - {\text{ }}4x{\text{ }} + {\text{ }}7\]. Here, we have to eliminate second term so we take coefficient of \[{x^3}\] to be zero, in other questions if it is asked to eliminate any other term we first substitute \[\left( {x + h} \right)\] in place of x, and then take the coefficient of the term which is asked to eliminate, as 0, and then we solve further.
Recently Updated Pages
What happens to glucose which enters nephron along class 10 biology CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

When the JanmiKudian Act was passed that granted the class 10 social science CBSE

A sector containing an angle of 120 circ is cut off class 10 maths CBSE

The sum of digits of a two digit number is 13 If t-class-10-maths-ICSE

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the missing number in the sequence 259142027 class 10 maths CBSE

