
The total numbers of square on a chessboard is:
A) \[206\]
B) \[205\]
C) \[204\]
D) \[202\]
Answer
582k+ views
Hint: At first, we have to find out how many positions there are that each size of square can be located.
A chess board contains \[1 \times 1\], \[2 \times 2\],\[3 \times 3\], \[4 \times 4\],\[5 \times 5\],\[6 \times 6\],\[7 \times 7\],\[8 \times 8\] square located in different places though can only fit in 1 position vertically and 1 horizontally.
We can find the locations for those squares, then we can find the sum of squares.
Complete step-by-step solution:
We have to find the total number of squares on a chessboard.
At first, we have to find out how many positions there are that each size of square can be located.
For example, a \[1 \times 1\] square can be located in 8 locations horizontally and 8 locations vertically that is in 64 different positions. An \[8 \times 8\] square though can only fit in 1 position vertically and 1 horizontally.
For example, a \[2 \times 2\] square can be located in 7 locations horizontally and 7 locations vertically that is in 49 different positions. An \[7 \times 7\] square though can only fit in 2 positions vertically and 2 horizontally.
So, we can prepare a table such as:
Hence, the total number of squares on a chessboard is 204.
Hence, the correct option is C.
Note: It is clear from the above analysis that the solution in case of \[n \times n\] is the sum of the squares from \[{n^2}\] to \[{1^2}\] that is to say
\[{n^2} + {(n - 1)^2} + {(n - 2)^2} + {(n - 3)^2} + ... + {2^2} + {1^2}\]
For a chessboard, \[n = 8\]
So, the total number of squares is \[{8^2} + {7^2} + {6^2} + {5^2} + ... + {2^2} + {1^2}\]
Solving we get, the total number of squares is \[ = 204\]
A chess board contains \[1 \times 1\], \[2 \times 2\],\[3 \times 3\], \[4 \times 4\],\[5 \times 5\],\[6 \times 6\],\[7 \times 7\],\[8 \times 8\] square located in different places though can only fit in 1 position vertically and 1 horizontally.
We can find the locations for those squares, then we can find the sum of squares.
Complete step-by-step solution:
We have to find the total number of squares on a chessboard.
At first, we have to find out how many positions there are that each size of square can be located.
For example, a \[1 \times 1\] square can be located in 8 locations horizontally and 8 locations vertically that is in 64 different positions. An \[8 \times 8\] square though can only fit in 1 position vertically and 1 horizontally.
For example, a \[2 \times 2\] square can be located in 7 locations horizontally and 7 locations vertically that is in 49 different positions. An \[7 \times 7\] square though can only fit in 2 positions vertically and 2 horizontally.
So, we can prepare a table such as:
| Size | Horizontal position | Vertical position | Positions |
| \[1 \times 1\] | 8 | 8 | 64 |
| \[2 \times 2\] | 7 | 7 | 49 |
| \[3 \times 3\] | 6 | 6 | 36 |
| \[4 \times 4\] | 5 | 5 | 25 |
| \[5 \times 5\] | 4 | 4 | 16 |
| \[6 \times 6\] | 3 | 3 | 9 |
| \[7 \times 7\] | 2 | 2 | 4 |
| \[8 \times 8\] | 1 | 1 | 1 |
| Total | 204 |
Hence, the total number of squares on a chessboard is 204.
Hence, the correct option is C.
Note: It is clear from the above analysis that the solution in case of \[n \times n\] is the sum of the squares from \[{n^2}\] to \[{1^2}\] that is to say
\[{n^2} + {(n - 1)^2} + {(n - 2)^2} + {(n - 3)^2} + ... + {2^2} + {1^2}\]
For a chessboard, \[n = 8\]
So, the total number of squares is \[{8^2} + {7^2} + {6^2} + {5^2} + ... + {2^2} + {1^2}\]
Solving we get, the total number of squares is \[ = 204\]
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Actinoid contraction is more than lanthanoid contraction class 11 chemistry CBSE

The transition element that has lowest enthalpy of class 11 chemistry CBSE

Can anyone list 10 advantages and disadvantages of friction

State the laws of reflection of light

