Answer
Verified
446.7k+ views
Hint: Valency theory & Chemical bonding model can tell about the number of electrons in one molecule of carbon dioxide. Valence bond theory considers that the overlapping atomic orbitals of the participating atoms form a chemical bond between the atoms and because of this overlapping, it is most probable that electrons should be available in the bond region. Valence bond theory views bonds as weakly coupled orbitals or small overlap.
Complete answer:
Carbon dioxide has the formula $C{{O}_{2}}$ and at the center of this linear molecule is a carbon atom joined by two pairs of double-bonds to the oxygen atoms, that is O=C=O. At room temperature carbon dioxide is a colorless gas which has a slightly sweet smell. Carbon dioxide $=C{{O}_{2}}$
Lewis structure
There are no loss/ gain of electrons during formation of $C{{O}_{2}}$
Hence from electronic configurations
$C:1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}:6{{e}^{-}}$
$O:1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}:8{{e}^{-}}$
electron in one carbon atom is 6 and electron present in two of the oxygen atom and hence total number of electrons $=6+2(8)=22$
$(C)+2(O)$
So, the correct answer is “Option A”.
Note: Lewis structures which are also known as Lewis dot diagrams or Lewis electron dot structures, are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.Lewis structures were only used to determine the type of bond and loss/gain of elections during the formation of compound in older times. Now, there are new and advanced theories.
Complete answer:
Carbon dioxide has the formula $C{{O}_{2}}$ and at the center of this linear molecule is a carbon atom joined by two pairs of double-bonds to the oxygen atoms, that is O=C=O. At room temperature carbon dioxide is a colorless gas which has a slightly sweet smell. Carbon dioxide $=C{{O}_{2}}$
Lewis structure
There are no loss/ gain of electrons during formation of $C{{O}_{2}}$
Hence from electronic configurations
$C:1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}:6{{e}^{-}}$
$O:1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}:8{{e}^{-}}$
electron in one carbon atom is 6 and electron present in two of the oxygen atom and hence total number of electrons $=6+2(8)=22$
$(C)+2(O)$
So, the correct answer is “Option A”.
Note: Lewis structures which are also known as Lewis dot diagrams or Lewis electron dot structures, are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.Lewis structures were only used to determine the type of bond and loss/gain of elections during the formation of compound in older times. Now, there are new and advanced theories.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Write a letter to the principal requesting him to grant class 10 english CBSE