Answer
424.2k+ views
Hint: Valency theory & Chemical bonding model can tell about the number of electrons in one molecule of carbon dioxide. Valence bond theory considers that the overlapping atomic orbitals of the participating atoms form a chemical bond between the atoms and because of this overlapping, it is most probable that electrons should be available in the bond region. Valence bond theory views bonds as weakly coupled orbitals or small overlap.
Complete answer:
Carbon dioxide has the formula $C{{O}_{2}}$ and at the center of this linear molecule is a carbon atom joined by two pairs of double-bonds to the oxygen atoms, that is O=C=O. At room temperature carbon dioxide is a colorless gas which has a slightly sweet smell. Carbon dioxide $=C{{O}_{2}}$
Lewis structure
There are no loss/ gain of electrons during formation of $C{{O}_{2}}$
Hence from electronic configurations
$C:1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}:6{{e}^{-}}$
$O:1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}:8{{e}^{-}}$
electron in one carbon atom is 6 and electron present in two of the oxygen atom and hence total number of electrons $=6+2(8)=22$
$(C)+2(O)$
So, the correct answer is “Option A”.
Note: Lewis structures which are also known as Lewis dot diagrams or Lewis electron dot structures, are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.Lewis structures were only used to determine the type of bond and loss/gain of elections during the formation of compound in older times. Now, there are new and advanced theories.
Complete answer:
Carbon dioxide has the formula $C{{O}_{2}}$ and at the center of this linear molecule is a carbon atom joined by two pairs of double-bonds to the oxygen atoms, that is O=C=O. At room temperature carbon dioxide is a colorless gas which has a slightly sweet smell. Carbon dioxide $=C{{O}_{2}}$
Lewis structure
![seo images](https://www.vedantu.com/question-sets/8077eb15-9769-40e9-9755-47eb0bc83cb54864695240283933818.png)
There are no loss/ gain of electrons during formation of $C{{O}_{2}}$
Hence from electronic configurations
$C:1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}:6{{e}^{-}}$
$O:1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}:8{{e}^{-}}$
electron in one carbon atom is 6 and electron present in two of the oxygen atom and hence total number of electrons $=6+2(8)=22$
$(C)+2(O)$
So, the correct answer is “Option A”.
Note: Lewis structures which are also known as Lewis dot diagrams or Lewis electron dot structures, are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.Lewis structures were only used to determine the type of bond and loss/gain of elections during the formation of compound in older times. Now, there are new and advanced theories.
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