
The total number of electrons in one molecule of carbon dioxide is (A)
A. 22
B. 44
C. 66
D. 88
Answer
483.3k+ views
Hint: Valency theory & Chemical bonding model can tell about the number of electrons in one molecule of carbon dioxide. Valence bond theory considers that the overlapping atomic orbitals of the participating atoms form a chemical bond between the atoms and because of this overlapping, it is most probable that electrons should be available in the bond region. Valence bond theory views bonds as weakly coupled orbitals or small overlap.
Complete answer:
Carbon dioxide has the formula $C{{O}_{2}}$ and at the center of this linear molecule is a carbon atom joined by two pairs of double-bonds to the oxygen atoms, that is O=C=O. At room temperature carbon dioxide is a colorless gas which has a slightly sweet smell. Carbon dioxide $=C{{O}_{2}}$
Lewis structure
There are no loss/ gain of electrons during formation of $C{{O}_{2}}$
Hence from electronic configurations
$C:1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}:6{{e}^{-}}$
$O:1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}:8{{e}^{-}}$
electron in one carbon atom is 6 and electron present in two of the oxygen atom and hence total number of electrons $=6+2(8)=22$
$(C)+2(O)$
So, the correct answer is “Option A”.
Note: Lewis structures which are also known as Lewis dot diagrams or Lewis electron dot structures, are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.Lewis structures were only used to determine the type of bond and loss/gain of elections during the formation of compound in older times. Now, there are new and advanced theories.
Complete answer:
Carbon dioxide has the formula $C{{O}_{2}}$ and at the center of this linear molecule is a carbon atom joined by two pairs of double-bonds to the oxygen atoms, that is O=C=O. At room temperature carbon dioxide is a colorless gas which has a slightly sweet smell. Carbon dioxide $=C{{O}_{2}}$
Lewis structure

There are no loss/ gain of electrons during formation of $C{{O}_{2}}$
Hence from electronic configurations
$C:1{{s}^{2}}2{{s}^{2}}2{{p}^{2}}:6{{e}^{-}}$
$O:1{{s}^{2}}2{{s}^{2}}2{{p}^{4}}:8{{e}^{-}}$
electron in one carbon atom is 6 and electron present in two of the oxygen atom and hence total number of electrons $=6+2(8)=22$
$(C)+2(O)$
So, the correct answer is “Option A”.
Note: Lewis structures which are also known as Lewis dot diagrams or Lewis electron dot structures, are diagrams that show the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.Lewis structures were only used to determine the type of bond and loss/gain of elections during the formation of compound in older times. Now, there are new and advanced theories.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE

The highest possible oxidation states of Uranium and class 11 chemistry CBSE

Find the value of x if the mode of the following data class 11 maths CBSE

Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE

A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State and prove Bernoullis theorem class 11 physics CBSE

What organs are located on the left side of your body class 11 biology CBSE

Write down 5 differences between Ntype and Ptype s class 11 physics CBSE
