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The time period of simple harmonic motion depends upon the
(A). Amplitude
(B). Energy
(C). Phase constant
(D). Mass

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Last updated date: 17th Apr 2024
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Answer
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Hint- In order to deal with this question we will use the formula of time period of the simple pendulum. We will check for all the options if they are directly or indirectly related to the period of simple harmonic motion.
Formula used- $T = 2\pi \sqrt {\dfrac{m}{k}} $

Complete step-by-step answer:

The time period of simple harmonic motion depends upon the mass.
For example- Simple pendulum,
The time period of the simple pendulum is given by
$T = 2\pi \sqrt {\dfrac{m}{k}} .........(1)$
From the above equation we can conclude that,
$
  \left( 1 \right)T \propto \sqrt m {\text{ }}\left( {{\text{m = mass of particle}}} \right) \\
  \left( 2 \right)T \propto \sqrt {\dfrac{1}{k}} {\text{ }}\left( {k = {\text{force constant}}} \right) \\
 $
Hence, the time period of simple harmonic motion depends upon the mass.
So, the correct option is D.

Note- Simple harmonic motion is a special type of periodic motion where the restoring force on the moving object is directly proportional to, and opposite of, the object's displacement vector. Examples of simple harmonic motion are the motion of a pendulum, motion of a spring, etc. Its applications are clock, guitar, violin, bungee jumping, rubber bands, diving boards etc.
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