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The teacher asked the students to read as much as possible of a particular book during the weekend. Balakrishnan read $\dfrac{1}{2}$of the book. Angela read $\dfrac{5}{6}$of the book and Subhalakshmi read $\dfrac{2}{3}$of the book. Arrange the three names in the order from the one who read the most of the least.

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Hint: To compare the fractions, make the denominators of all the fractions same. Then arrange the fractions in decreasing order (according to question).

Complete step-by-step answer:
Let us compare the fractions by making the denominators of all the fractions the same.
Therefore, book read by Balakrishnan is, $\dfrac{1}{2} = \dfrac{{1{\text{x3}}}}{{2{\text{x}}3}} = \dfrac{3}{6}$th of the total.
Book read by Angela is $\dfrac{5}{6}$th of the total.
And portion read by Subhalakshmi is $\dfrac{2}{3} = \dfrac{{2{\text{x2}}}}{{3{\text{x2}}}} = \dfrac{4}{6}$th of the total.
 Now arranging the fractions in decreasing order we get, $\dfrac{5}{6} > \dfrac{4}{6} > \dfrac{3}{6}$
Therefore, the order from the one who read the book most to the least is:
Angela, Subhalakshmi, Balakrishnan. (answer)

Note: To compare the fractions, make the denominators of all the fractions same.
Then compare the numerators. The greater the value of the numerator is, the greater is the value of the fraction.