
The sum of three numbers in the A.P. is – 3, and the product of these three numbers is equal to 8. Then find these three numbers.
Answer
600k+ views
Hint: Let us assume the three terms of the A.P such that when we add these three terms then we are left with only one variable So, that we can find the value of that variable by putting the sum of three terms equal to zero.
Complete Step-by-Step solution:
Now, as we know that the common difference of an A.P is the difference of any two the consecutive terms of that A.P.
So, now we have two find three terms of an A.P which follow the given conditions.
Let the second term of the three terms be a.
And the common difference of the A.P will be d.
So, second term – first term = d
So, a – first term = d
First term of the A.P will be a - d.
And, third term – second term = d
Third term – a = d
Third term = a + d
So, the required three terms of the A.P will be a – d, a, a + d.
Now as we know that the sum of the three terms is equal to – 3.
So, (a – d) + (a) + (a + d) = – 3
3a = – 3
a = – 1
As it is given in the question that the product of these three terms is equal to 8.
So, (a – d)*(a)*(a + d) = 8
Now solving the above equation. We get,
\[
\left( {{a^2} - ad} \right)*\left( {a + d} \right) = 8 \\
{a^3} + {a^2}d - {a^2}d - a{d^2} = 8 \\
{a^3} - a{d^2} = 8 \\
\]
Now we had to put the value of a = - 1 in the above equation. We get,
\[ - 1 + {d^2} = 8\]
Now adding 1 to both sides of the above equation we get,
\[
{d^2} = 9 \\
d = \pm 3 \\
\]
Now d can have two values 3 or – 3. But a = - 1.
So, now we had to find the three terms of the A.P
If d = 3
First term of the A.P will be = a – d = – 1 – 3 = – 4.
Second term of the A.P will be = a = – 1
Third term of the A.P will be = a + d = – 1 + 3 = 2.
If d = – 3
First term of the A.P will be = a – d = – 1 –(– 3) = 2.
Second term of the A.P will be = a = – 1.
Third term of the A.P will be = a + d = – 1 – 3 = – 4.
Hence, the three terms of the A.P such that their sum is – 3 and product is 8 is equal to (– 4, – 1, 2) or (2, –1, – 4).
Note: Whenever we come up with a type of problem then first, we have to assume the middle term is equal to any variable and then we assume first and third term such that they are less and more than middle term by a common difference d respectively. After adding three terms we get the value of the middle term(b) and then we multiply all three terms to get the value of d. After that putting the value of a and d we will get the three terms of the A.P.
Complete Step-by-Step solution:
Now, as we know that the common difference of an A.P is the difference of any two the consecutive terms of that A.P.
So, now we have two find three terms of an A.P which follow the given conditions.
Let the second term of the three terms be a.
And the common difference of the A.P will be d.
So, second term – first term = d
So, a – first term = d
First term of the A.P will be a - d.
And, third term – second term = d
Third term – a = d
Third term = a + d
So, the required three terms of the A.P will be a – d, a, a + d.
Now as we know that the sum of the three terms is equal to – 3.
So, (a – d) + (a) + (a + d) = – 3
3a = – 3
a = – 1
As it is given in the question that the product of these three terms is equal to 8.
So, (a – d)*(a)*(a + d) = 8
Now solving the above equation. We get,
\[
\left( {{a^2} - ad} \right)*\left( {a + d} \right) = 8 \\
{a^3} + {a^2}d - {a^2}d - a{d^2} = 8 \\
{a^3} - a{d^2} = 8 \\
\]
Now we had to put the value of a = - 1 in the above equation. We get,
\[ - 1 + {d^2} = 8\]
Now adding 1 to both sides of the above equation we get,
\[
{d^2} = 9 \\
d = \pm 3 \\
\]
Now d can have two values 3 or – 3. But a = - 1.
So, now we had to find the three terms of the A.P
If d = 3
First term of the A.P will be = a – d = – 1 – 3 = – 4.
Second term of the A.P will be = a = – 1
Third term of the A.P will be = a + d = – 1 + 3 = 2.
If d = – 3
First term of the A.P will be = a – d = – 1 –(– 3) = 2.
Second term of the A.P will be = a = – 1.
Third term of the A.P will be = a + d = – 1 – 3 = – 4.
Hence, the three terms of the A.P such that their sum is – 3 and product is 8 is equal to (– 4, – 1, 2) or (2, –1, – 4).
Note: Whenever we come up with a type of problem then first, we have to assume the middle term is equal to any variable and then we assume first and third term such that they are less and more than middle term by a common difference d respectively. After adding three terms we get the value of the middle term(b) and then we multiply all three terms to get the value of d. After that putting the value of a and d we will get the three terms of the A.P.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

