The slope of tangents drawn from a point (4, 10) to the parabola ${y^2} = 9x$are
$
A.{\text{ }}\dfrac{1}{4},\dfrac{3}{4} \\
B.{\text{ }}\dfrac{9}{4},\dfrac{1}{4} \\
C.{\text{ }}\dfrac{1}{3},\dfrac{1}{4} \\
D. None of these
$
Answer
642.3k+ views
Hint: - Here we go through by the general term of parabola i.e. ${y^2} = 4ax$ .As we know the equation of tangent to this parabola is$y = mx + \dfrac{a}{m}$. So simply put the values and then find the value of m to get the slopes.
Complete step-by-step solution -
Here in the question the given parabola is ${y^2} = 9x$ if we compare this parabola with the general form of parabola we get, $4a = 9$ i.e. $a = \dfrac{9}{4}$.
We know that the equation of tangent to the parabola ${y^2} = 4ax$ is$y = mx + \dfrac{a}{m}$.
After putting the values of ‘a’ in tangent equation we get, $y = mx + \dfrac{9}{{4m}}$
And in the question it is given that the tangent is passing from the point (4, 10) so this point should satisfy in the tangent equation,
I.e. $10 = 4m + \dfrac{9}{{4m}}$ after solving this equation we get the value of m.
$
\Rightarrow 16{m^2} - 40m + 9 = 0 \\
\Rightarrow 16{m^2} - 4m - 36m + 9 = 0 \\
\Rightarrow 4m(4m - 1) - 9(4m - 1) = 0 \\
\Rightarrow (4m - 1)(4m - 9) = 0 \\
$
$\therefore m = \dfrac{1}{4},\dfrac{9}{4}$ This is the required slope of the tangent as we know in the tangent equation m represents a slope.
Hence, option B is the correct answer.
Note:- Whenever we face such a type of question the key concept for solving the question is compare the parabola equation with the general form of parabola to find the value of a. Here it is the question on tangent so we write the general equation of tangent on general form of parabola, then put the value of ‘a’ to find the equation of tangent to the parabola that is given in the question. And then put the points from where the tangent is passing by these steps so we can find out the slope of the tangent.
Complete step-by-step solution -
Here in the question the given parabola is ${y^2} = 9x$ if we compare this parabola with the general form of parabola we get, $4a = 9$ i.e. $a = \dfrac{9}{4}$.
We know that the equation of tangent to the parabola ${y^2} = 4ax$ is$y = mx + \dfrac{a}{m}$.
After putting the values of ‘a’ in tangent equation we get, $y = mx + \dfrac{9}{{4m}}$
And in the question it is given that the tangent is passing from the point (4, 10) so this point should satisfy in the tangent equation,
I.e. $10 = 4m + \dfrac{9}{{4m}}$ after solving this equation we get the value of m.
$
\Rightarrow 16{m^2} - 40m + 9 = 0 \\
\Rightarrow 16{m^2} - 4m - 36m + 9 = 0 \\
\Rightarrow 4m(4m - 1) - 9(4m - 1) = 0 \\
\Rightarrow (4m - 1)(4m - 9) = 0 \\
$
$\therefore m = \dfrac{1}{4},\dfrac{9}{4}$ This is the required slope of the tangent as we know in the tangent equation m represents a slope.
Hence, option B is the correct answer.
Note:- Whenever we face such a type of question the key concept for solving the question is compare the parabola equation with the general form of parabola to find the value of a. Here it is the question on tangent so we write the general equation of tangent on general form of parabola, then put the value of ‘a’ to find the equation of tangent to the parabola that is given in the question. And then put the points from where the tangent is passing by these steps so we can find out the slope of the tangent.
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