The runs scored by the two teams A and B on the first 60 balls in a cricket match are given below:
Represent the data of both the teams on the same graph by frequency polygons.
Number of balls Team A Team B 1-16 2 5 7-12 1 6 13-18 8 2 19-24 9 10 25-30 4 5 31-36 5 6 37-42 6 3 43-48 10 4 49-54 6 8 55-60 2 10
| Number of balls | Team A | Team B |
| 1-16 | 2 | 5 |
| 7-12 | 1 | 6 |
| 13-18 | 8 | 2 |
| 19-24 | 9 | 10 |
| 25-30 | 4 | 5 |
| 31-36 | 5 | 6 |
| 37-42 | 6 | 3 |
| 43-48 | 10 | 4 |
| 49-54 | 6 | 8 |
| 55-60 | 2 | 10 |
Answer
626.1k+ views
Hint: First of all we have to know what frequency polygons are, a frequency polygon is a graphical form of representation of data. The relevance of presentation of data in the pictorial or graphical form is immense. Frequency polygon, it is used to depict the shape of the data and to depict trends. It is usually drawn with the help of a histogram but can be drawn without it as well. So basically the frequency polygon is a graphical device for understanding the shapes of distributions.
Complete step-by-step solution:
Here it is given the problem that there are 2 teams named A and B, and their scored runs in the first 60 balls in a cricket match.
Let us learn the step by step process of drawing a frequency polygon:
First we have to calculate the class mark of each class interval. Where the formula for the class mark is given by:
$ \Rightarrow $Class mark = (Upper limit + Lower limit) / 2
The class marks are also known as the mid-value of each class.
Now mark the class marks for each class interval on the horizontal axis.
Plotting the runs of each team on the vertical axis.
Corresponding to each class mark, plot the runs of both the teams as given.
The height always depicts the runs scored by the teams.
We have to make sure that the runs scored by the teams are plotted against the class mark but not the upper or lower limit of the class interval.
Now join all the plotted points using a line segment. The curve obtained here will be kinked, this is called the frequency polygon graph.
Hence the resulting curve is called the frequency polygon.
Now plotting the frequency polygon here, as given below:
Note: Frequency polygons are a good choice for displaying cumulative frequency distributions. Also note that we can also draw a frequency polygon with the use of a histogram as well, by joining the midpoints of the bars.
Complete step-by-step solution:
Here it is given the problem that there are 2 teams named A and B, and their scored runs in the first 60 balls in a cricket match.
Let us learn the step by step process of drawing a frequency polygon:
First we have to calculate the class mark of each class interval. Where the formula for the class mark is given by:
$ \Rightarrow $Class mark = (Upper limit + Lower limit) / 2
The class marks are also known as the mid-value of each class.
Now mark the class marks for each class interval on the horizontal axis.
Plotting the runs of each team on the vertical axis.
Corresponding to each class mark, plot the runs of both the teams as given.
The height always depicts the runs scored by the teams.
We have to make sure that the runs scored by the teams are plotted against the class mark but not the upper or lower limit of the class interval.
Now join all the plotted points using a line segment. The curve obtained here will be kinked, this is called the frequency polygon graph.
Hence the resulting curve is called the frequency polygon.
Now plotting the frequency polygon here, as given below:
Note: Frequency polygons are a good choice for displaying cumulative frequency distributions. Also note that we can also draw a frequency polygon with the use of a histogram as well, by joining the midpoints of the bars.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

The teeth used for biting and cutting food are called class 11 biology CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

Frogs heart when taken out of the body continues to class 11 biology CBSE

10 examples of diffusion in everyday life

Can anyone list 10 advantages and disadvantages of friction

