The relation between momentum(P), mass(m), Kinetic energy(KE) and velocity(V) of the body is:
A. $PV = 2KE$
B. $KE = \dfrac{{{P^2}}}{{2m}}$
C. ${P^2} = 2mKE$
D. All of the above.
Answer
654.6k+ views
- Hint: In this question, we should have some basic knowledge of the terms that are given in the question. We will use the definition and formulae of those terms to find out the relation between them.
Complete step-by-step solution -
Momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.
Kinetic energy is the product of one-half of the mass of the body and the square of its velocity or speed. It is a scalar quantity.
We know that the momentum and the kinetic energy of a moving body are the body’s properties which is very much related to velocity.
We have, $KE = \dfrac{1}{2}m{V^2}$ and $P = mV$
Now,
$
\Rightarrow KE = \dfrac{1}{2}m{V^2} \\
\Rightarrow 2KE = m{V^2} \\
\Rightarrow 2KE = (mV)V \\
$
Putting P = mV we get,
$ \Rightarrow 2KE = PV$ ……….(i)
Multiplying ‘m’ both sides, we get
$ \Rightarrow 2mKE = PmV$, again put P=mV
$ \Rightarrow 2mKE = {P^2}$ ………..(ii)
$ \Rightarrow KE = \dfrac{{{P^2}}}{{2m}}$ ……..(iii)
Hence, from equations (i), (ii) and (iii) we can say that options A, B and C are correct. Therefore option D – all of the above is correct.
Note: In this type of questions, first we have to write the definition and the formulae of the terms that are given in the question. Then we will find that either other term is occurring in the formulae of one term or not. If so , then we will put that term in the formula, and through we will get the relationship of these terms .
Complete step-by-step solution -
Momentum, product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.
Kinetic energy is the product of one-half of the mass of the body and the square of its velocity or speed. It is a scalar quantity.
We know that the momentum and the kinetic energy of a moving body are the body’s properties which is very much related to velocity.
We have, $KE = \dfrac{1}{2}m{V^2}$ and $P = mV$
Now,
$
\Rightarrow KE = \dfrac{1}{2}m{V^2} \\
\Rightarrow 2KE = m{V^2} \\
\Rightarrow 2KE = (mV)V \\
$
Putting P = mV we get,
$ \Rightarrow 2KE = PV$ ……….(i)
Multiplying ‘m’ both sides, we get
$ \Rightarrow 2mKE = PmV$, again put P=mV
$ \Rightarrow 2mKE = {P^2}$ ………..(ii)
$ \Rightarrow KE = \dfrac{{{P^2}}}{{2m}}$ ……..(iii)
Hence, from equations (i), (ii) and (iii) we can say that options A, B and C are correct. Therefore option D – all of the above is correct.
Note: In this type of questions, first we have to write the definition and the formulae of the terms that are given in the question. Then we will find that either other term is occurring in the formulae of one term or not. If so , then we will put that term in the formula, and through we will get the relationship of these terms .
Recently Updated Pages
The given figure shows two endocrine glands marked class 11 biology NEET_UG

Match columnI with columnII and select the correct class 11 biology NEET

Match column I with column II and select the correct class 11 biology NEET_UG

Which floral family has left 9 right + 1 arrangement class 11 biology NEET_UG

Which is not a variety of sheep A Lohi B Beetal C Nellore class 11 biology NEET_UG

Match column I with column II and select the correct class 11 biology NEET_UG

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is cell theory Who formulated it class 11 biology CBSE

Phyllotaxy is the arrangement of ALeaflets BLeaves class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

The symbiotic association of fungi and algae is called class 11 biology CBSE

Cell theory was formulated by A Schleiden and Schwann class 11 biology CBSE

