Question

The reaction of propene with ${{H}_{3}}{{O}^{+}}$will proceed with which of the following intermediate?
A.

B.

C.

D.

Answer 1

Hint:The reaction where any alkene is subjected to the addition of water molecules is known as hydration reaction. The hydration of alkenes yields alcohol. This reaction is based on markovnikov rule, and is a type of electrophilic addition reaction.

Complete step-by-step answer:The reaction where alkenes react with water is known as hydration of alkenes. It follows the Markovnikov rule that states that the negative part of the addendum goes to that carbon of the carbon- carbon double bond which has less number of hydrogen atoms.
Therefore, a reactive intermediate is formed in these types of reactions where the water molecule gets attached to the carbon according to the markovnikov rule. The reaction happens in 3 steps, in the first step the protonation occurs, then the water molecule gets attached, and in the last step deprotonation occurs to form an alcohol.
For propene, the hydration occurs as follows,

A carbocation is formed after protonation, and then the electrophile of water attacks this carbocation, forming an intermediate, which on deprotonation forms 2-propanol.
As the reaction is according to Markovnikov rule, so the intermediate is option C, that has water attached with carbon that has less hydrogen atoms.

Hence, option C is correct.

Note:Addition of water to alkenes happens in the similar way as that of addition of halogen acids, as water and halogen acids both have the same type of H-X bond which have the ability to donate protons.