
The ratio of the weight of an object on the earth to the moon is \[6:1\]. If a man weighs 29 pounds on the moon, calculate his weighing on the earth.
(A) 21
(B) 48
(C) 174
(D) 196
Answer
590.1k+ views
Hint: Given that the weight of an object on the earth to the moon is \[6:1\]
Therefore,
$\dfrac{{{\text{weight of an object on the earth}}}}{{{\text{weight of an object on the moon}}}} = \dfrac{6}{1}$
Now in the question, the man’s weight on the moon is given. Hence, we can find his weight on the earth, by substituting the given value and on solving.
Complete step by step answer:
Given that the weight of an object on the earth to the moon is 6:1
Therefore,
$\dfrac{{{\text{weight of an object on the earth}}}}{{{\text{weight of an object on the moon}}}} = \dfrac{6}{1}$
$ \Rightarrow {\text{weight of an object on the earth}} = 6 \times {\text{weight of an object on the moon}}$
Now according to the question the man weighs 29 pounds on the moon,
Therefore, weight of the man on earth will be
$ = 6 \times {\text{weight of the man on the moon}}$
On substituting the value we get,
$ = 6 \times 29 = 174$ pounds.
Hence the correct option is (C).
Note: If ratio of A to B is given by \[x:y\],
Therefore $\dfrac{A}{B} = \dfrac{x}{y}$
(e.g.) Given that the weight of an object on the earth to the moon is 6:1.
Therefore,
$\dfrac{{{\text{weight of an object on the earth}}}}{{{\text{weight of an object on the moon}}}} = \dfrac{6}{1}$
Therefore,
$\dfrac{{{\text{weight of an object on the earth}}}}{{{\text{weight of an object on the moon}}}} = \dfrac{6}{1}$
Now in the question, the man’s weight on the moon is given. Hence, we can find his weight on the earth, by substituting the given value and on solving.
Complete step by step answer:
Given that the weight of an object on the earth to the moon is 6:1
Therefore,
$\dfrac{{{\text{weight of an object on the earth}}}}{{{\text{weight of an object on the moon}}}} = \dfrac{6}{1}$
$ \Rightarrow {\text{weight of an object on the earth}} = 6 \times {\text{weight of an object on the moon}}$
Now according to the question the man weighs 29 pounds on the moon,
Therefore, weight of the man on earth will be
$ = 6 \times {\text{weight of the man on the moon}}$
On substituting the value we get,
$ = 6 \times 29 = 174$ pounds.
Hence the correct option is (C).
Note: If ratio of A to B is given by \[x:y\],
Therefore $\dfrac{A}{B} = \dfrac{x}{y}$
(e.g.) Given that the weight of an object on the earth to the moon is 6:1.
Therefore,
$\dfrac{{{\text{weight of an object on the earth}}}}{{{\text{weight of an object on the moon}}}} = \dfrac{6}{1}$
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