Question

The ratio of the electric force between two electrons to the gravitational force between them is of the order of:
(A) $ {{10}^{42}} $
(B) $ {{10}^{40}} $
(C) $ {{10}^{36}} $
(D) $ {{10}^{32}} $

Answer 1

Hint
Gravity is a force of attraction that exists between any two masses, any two bodies, any two particles. Gravity is not just the attraction between objects and the Earth. Actually, gravity is the weakest of the four fundamental forces. Because they both have mass, the two protons exert gravitational attraction on each other. Because they both have a positive electric charge, they both exert electromagnetic repulsion on each other. The attractive force that the celestial bodies exert on other masses by virtue of their total mass is called the force of gravity. The force of mutual attraction force of gravity is then that much more significant, the greater the mass of the objects between which it acts. Based on this concept we have to solve this question.

Complete step by step answer
We know that,
Charge on an electron $ \mathrm{q}=-1.6 \times 10^{-19} \mathrm{C} $
Mass of an electron, $ \mathrm{m}=9.1 \times 10^{-31} \mathrm{kg} $
gravitational constant, $ \mathrm{g}=6.67 \times 10^{-11} $
Let the distance between two electrons $ =\mathrm{r} $
Therefore, we can determine that the electric force,
 $ \mathrm{K}^{\prime}=9 \times 10^{9} $
gravitational force,
 $ \mathrm{F}_{\mathrm{q}}=\dfrac{\mathrm{K}(\mathrm{q})^{2}}{\mathrm{r}^{2}} $
Now,
$\dfrac{{{\text{F}}_{\text{e}}}}{{{\text{F}}_{\text{g}}}}=\dfrac{\text{k}{{\text{q}}^{2}}}{{{\text{r}}^{2}}}\times \dfrac{{{\text{r}}^{2}}}{\text{G}{{\text{m}}^{2}}} $
 $ =\dfrac{9 \times 10^{9} \times\left(-1.6 \times 10^{-19}\right)^{2}}{6.67 \times 10^{-11} \times\left(9.1 \times 10^{-31}\right)^{2}} $
 $ =4.17 \times 10^{42} $

Hence, the correct answer is Option (A).

Note
It should be known to us that in physics, a gravitational field is a model used to explain the influence that a massive body extends into the space around itself, producing a force on another massive body. Thus, a gravitational field is used to explain gravitational phenomena, and is measured in newtons per kilogram. If an object falls from one point to another point inside a gravitational field, the force of gravity will do positive work on the object, and the gravitational potential energy will decrease by the same amount. When the book hits the floor, this kinetic energy is converted into heat and sound by the impact. Gravitational fields are vector fields. They can be visualized in two ways - either by drawing an arrow representing the gravitational field vector at that point, or by drawing field lines.