Question

# The rate of change of momentum representsA. PressureB. ForceC. WorkD. Kinetic energy

Hint: Go with the basic definition of momentum and take the rate of change of momentum with respect to time in mathematical terms to derive the result.
Formula used: The formula from the basic definition of momentum is used.
$\text{momentum}=\text{mass}\times \text{velocity}$

Momentum for an object is defined as the quantity of its motion. The momentum of an object is the virtue of its mass and the velocity of its motion.
For ease of solving the question, let us denote the momentum of the object as $p$, let the mass of the object be $m$, and the velocity at any instant be $v$.
The question requires a change in momentum with respect to time $t$. Let us consider a small change in the system and thus take a differential change.
Therefore, the expression takes the form:
$\Rightarrow \dfrac{dp}{dt}$
But the formula for momentum is known to us.
\begin{align} & \text{momentum}=\text{mass}\times \text{velocity} \\ & p=mv \\ \end{align}
Thus, the expression becomes:
$\Rightarrow \dfrac{dp}{dt}=\dfrac{d(mv)}{dt}=m\dfrac{dv}{dt}$
Look at the expression, the term $\dfrac{dv}{dt}$ is nothing but the expression of instantaneous acceleration.
And we know that mass times acceleration is force. Where, force is a push or pull on an object resulting from the object's interaction with another object.
Therefore,
$\Rightarrow m\dfrac{dv}{dt}=ma=\text{Force}$
Thus, the answer to this question is option B. force.

Note: Firstly, while taking the derivative of momentum, it is an assumption that the mass of the object remains constant. Therefore, differentiation does not apply on $m$. Secondly, one another way to solve this problem can be by performing dimensional analysis on the quantity asked in the question and matching it with the options.