
The radius in kilometers, to which the present radius of the earth ( ) is to be compressed so that the escape velocity is increased ten times is:
A. 6.4
B. 64
C. 640
D. 4800
Answer
503.7k+ views
Hint: The escape velocity of earth is the velocity required by the object to escape the gravitational field of earth. It is inversely proportional to the square root of the radius of Earth. Using this relation, we can find the radius to which the Earth is to be compressed, such that the radius of Earth is ten times the initial escape velocity of Earth.
Formula used:
Complete answer:
Escape velocity is the velocity required to escape the Earth’s gravity field. It is mathematically given by
Where
is the escape velocity of Earth
is the gravitational constant
is the mass of the Earth
is the radius of Earth
From the above relation we can understand that
Using this we, deduce the relation
Here,
is the initial escape velocity of Earth
is the initial radius of Earth
is the final escape velocity of Earth
is the final radius of Earth
It is mentioned in the question, that .
Let, where x is the no. of times the initial radius is compressed to. Substituting these in the formula
We have,
Now, we have the new radius as
So, the correct answer is “Option B”.
Note:
In the question, nothing is mentioned about mass. For this reason, we assume that the mass is constant throughout the problem. The student should look out if change in mass is mentioned, as it might affect the solution. In that case, the formula is as follows
Formula used:
Complete answer:
Escape velocity is the velocity required to escape the Earth’s gravity field. It is mathematically given by
Where
From the above relation we can understand that
Using this we, deduce the relation
Here,
It is mentioned in the question, that
Let,
We have,
Now, we have the new radius as
So, the correct answer is “Option B”.
Note:
In the question, nothing is mentioned about mass. For this reason, we assume that the mass is constant throughout the problem. The student should look out if change in mass is mentioned, as it might affect the solution. In that case, the formula is as follows
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