
The quadratic polynomial having zeros are 1 and -2 is.
(a) ${{x}^{2}}-x-2$
(b) ${{x}^{2}}-x+2$
(c) ${{x}^{2}}+x-2$
(d) ${{x}^{2}}+x+2$
Answer
594.9k+ views
Hint: For solving this question we will simply find the sum and the product of the given roots and substitute their values in the formula ${{x}^{2}}-\left( \text{sum of the roots} \right)x+\left( \text{product of the roots} \right)$ to get the required quadratic polynomial. After that, we will see the plot of the polynomial and verify our answer.
Complete step-by-step solution -
Given:
We have to find the quadratic polynomial having roots 1 and -2.
Now, before we proceed we should know that if $x=\alpha $ and $x=\beta $ are roots of a quadratic polynomial $\left( x-\alpha \right)\left( x-\beta \right)={{x}^{2}}-\left( \alpha +\beta \right)x+\alpha \beta $ and we can write it as ${{x}^{2}}-\left( \text{sum of the roots} \right)x+\left( \text{product of the roots} \right)$ .
Now, we come back to our question in which we have to find the quadratic polynomial having roots 1 and 2. And from the above discussion, we can say that the required polynomial will be $\left( x-\alpha \right)\left( x-\beta \right)={{x}^{2}}-\left( \alpha +\beta \right)x+\alpha \beta $ with the value of $\alpha =1$ and $\beta =-2$ . Then,
$\begin{align}
& \left( x-\alpha \right)\left( x-\beta \right)={{x}^{2}}-\left( \alpha +\beta \right)x+\alpha \beta \\
& \Rightarrow \left( x-1 \right)\left( x+2 \right)={{x}^{2}}-\left( 1-2 \right)x-2 \\
& \Rightarrow \left( x-1 \right)\left( x+2 \right)={{x}^{2}}+x-2 \\
\end{align}$
Now, from the above result, we conclude that the quadratic polynomial having zeros 1 and -2 will be ${{x}^{2}}+x-2$ . For better clarity look at the figure below:
In the above figure, the curve $y={{x}^{2}}+x-2$ intersects the x-axis at two points A (-2,0) and B (1,0) and it is evident that ${{x}^{2}}+x-2$ is the quadratic polynomial having zeros 1 and -2.
Thus, ${{x}^{2}}+x-2$ is the required quadratic polynomial.
Hence, option (c) will be the correct option.
Note: Here, the student should first understand what is asked in the question and then proceed in the right direction to get the correct answer quickly. Moreover, though the problem is very easy, but we should write the expression of the required polynomial without any mistake and in the end, we should verify our answer with a graph and strengthen our basic concepts.
Complete step-by-step solution -
Given:
We have to find the quadratic polynomial having roots 1 and -2.
Now, before we proceed we should know that if $x=\alpha $ and $x=\beta $ are roots of a quadratic polynomial $\left( x-\alpha \right)\left( x-\beta \right)={{x}^{2}}-\left( \alpha +\beta \right)x+\alpha \beta $ and we can write it as ${{x}^{2}}-\left( \text{sum of the roots} \right)x+\left( \text{product of the roots} \right)$ .
Now, we come back to our question in which we have to find the quadratic polynomial having roots 1 and 2. And from the above discussion, we can say that the required polynomial will be $\left( x-\alpha \right)\left( x-\beta \right)={{x}^{2}}-\left( \alpha +\beta \right)x+\alpha \beta $ with the value of $\alpha =1$ and $\beta =-2$ . Then,
$\begin{align}
& \left( x-\alpha \right)\left( x-\beta \right)={{x}^{2}}-\left( \alpha +\beta \right)x+\alpha \beta \\
& \Rightarrow \left( x-1 \right)\left( x+2 \right)={{x}^{2}}-\left( 1-2 \right)x-2 \\
& \Rightarrow \left( x-1 \right)\left( x+2 \right)={{x}^{2}}+x-2 \\
\end{align}$
Now, from the above result, we conclude that the quadratic polynomial having zeros 1 and -2 will be ${{x}^{2}}+x-2$ . For better clarity look at the figure below:
In the above figure, the curve $y={{x}^{2}}+x-2$ intersects the x-axis at two points A (-2,0) and B (1,0) and it is evident that ${{x}^{2}}+x-2$ is the quadratic polynomial having zeros 1 and -2.
Thus, ${{x}^{2}}+x-2$ is the required quadratic polynomial.
Hence, option (c) will be the correct option.
Note: Here, the student should first understand what is asked in the question and then proceed in the right direction to get the correct answer quickly. Moreover, though the problem is very easy, but we should write the expression of the required polynomial without any mistake and in the end, we should verify our answer with a graph and strengthen our basic concepts.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
Who was the first woman to receive Bharat Ratna?

Write a letter to the principal requesting him to grant class 10 english CBSE

Why is there a time difference of about 5 hours between class 10 social science CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Discuss the main reasons for poverty in India

