Question

What will be the product when $$C_6{H}_{6}C{l}_6$$ is heated with alc. KOH? Explain the mechanism too.

Answer 1

Hint: A removal response is a kind of natural response wherein substituents are eliminated from a molecule in both a one- or -step mechanism. The one-step mechanism is called the E2 response, and the -step mechanism is called the E1 response. The numbers refer now no longer to the variety of steps withinside the mechanism, however instead to the kinetics of the response: E2 is bimolecular (2d-order) at the same time as E1 is unimolecular (first-order).

Complete answer:
The response will arise if all the atoms are in identical facets i.e. syn and the response will now no longer arise if the atoms are changed syn and anti.
E2 response is an Anti-removal response so see withinside the reaction given below:
1) In the first case the response will arise due to the fact the adjacent and atoms are Anti, so removal is required.

2) In the second case the response will now no longer arise due to the fact the adjacent and atoms are Syn so removal isn't always viable there in 2d case.

Note:
Syn addition is the addition of substituents to the identical facet (or face) of a double bond or triple bond, ensuing in a lower in bond order however a boom in the variety of substituents at the same time as in Anti addition is in direct comparison to syn addition. In anti addition, substituents are introduced to contrary sides (or faces) of a double bond or triple bond, over again ensuing in a lower in bond order and boom in the variety of substituents.