
The product of two numbers is $37$. What is the square root of their difference?
Answer
555.9k+ views
Hint:
Assume the numbers to be ‘a’ and ‘b’. Here we can see that $37$ is a prime number. Prime numbers are numbers that are only divisible by themselves and $1$. Then find the difference of the obtained numbers and at last find the square root of the difference obtained.
Complete step by step solution:
Given, the product of two numbers is$37$.We have to find the square root of their differences.
If ‘a’ and b are the two numbers whose product is $37$ then we are going to find $a - b$ first, then if $a - b = c$ (let) then we are going to find its square root. i.e.$\sqrt c $
We now that $37$is a prime number which means it has only two factors $37$ and $1$ so we know the value of ‘a’ and ‘b’ Now we are going to find$a - b$. On Subtracting b from a, we get-
$ \Rightarrow 37 - 1 = 36$
Now, we have to find the square-root of $36$. We know that$36$ is a perfect square.
We can find its square root by finding its factors by dividing it by the smallest prime number which is $2$
$ \Rightarrow \dfrac{{36}}{2} = 18$
Then again divide the obtained number by the smallest prime number (from which the number is divisible)
$ \Rightarrow \dfrac{{18}}{2} = 9$
Then again divide the obtained number by the smallest prime number (from which the number is divisible)
$ \Rightarrow \dfrac{9}{3} = 3$
Again divide the obtained number by the smallest prime number (from which the number is divisible)
$ \Rightarrow \dfrac{3}{{3 = 1}}$
So we can write the factors as-
$ \Rightarrow \sqrt {36} = \sqrt {2 \times 2 \times 3 \times 3} $
On solving, we get-
$ \Rightarrow \sqrt {36} = 2 \times 3$
On multiplication, we get-
$ \Rightarrow \sqrt {36} = 6$
Answer- The correct answer is $6$.
Note:
Here you can also explain this question in the following way-
Since a and b are the two numbers whose product is $37$ so we can write-
$ \Rightarrow a \times b = 37$
On rearranging, we can write-
$ \Rightarrow a = \dfrac{{37}}{b}$
Now since we know that $37$ is a prime number so $b$ is equal to either $1$ or $37$ so on putting its value in the above equation, we get-
$ \Rightarrow $ If a$ = 1$ then b$ = 37$ or if $a = 37$ then b=$1$
Now, we can easily find the difference between the two numbers and solve the question further as we have done in the above solution.
Assume the numbers to be ‘a’ and ‘b’. Here we can see that $37$ is a prime number. Prime numbers are numbers that are only divisible by themselves and $1$. Then find the difference of the obtained numbers and at last find the square root of the difference obtained.
Complete step by step solution:
Given, the product of two numbers is$37$.We have to find the square root of their differences.
If ‘a’ and b are the two numbers whose product is $37$ then we are going to find $a - b$ first, then if $a - b = c$ (let) then we are going to find its square root. i.e.$\sqrt c $
We now that $37$is a prime number which means it has only two factors $37$ and $1$ so we know the value of ‘a’ and ‘b’ Now we are going to find$a - b$. On Subtracting b from a, we get-
$ \Rightarrow 37 - 1 = 36$
Now, we have to find the square-root of $36$. We know that$36$ is a perfect square.
We can find its square root by finding its factors by dividing it by the smallest prime number which is $2$
$ \Rightarrow \dfrac{{36}}{2} = 18$
Then again divide the obtained number by the smallest prime number (from which the number is divisible)
$ \Rightarrow \dfrac{{18}}{2} = 9$
Then again divide the obtained number by the smallest prime number (from which the number is divisible)
$ \Rightarrow \dfrac{9}{3} = 3$
Again divide the obtained number by the smallest prime number (from which the number is divisible)
$ \Rightarrow \dfrac{3}{{3 = 1}}$
So we can write the factors as-
$ \Rightarrow \sqrt {36} = \sqrt {2 \times 2 \times 3 \times 3} $
On solving, we get-
$ \Rightarrow \sqrt {36} = 2 \times 3$
On multiplication, we get-
$ \Rightarrow \sqrt {36} = 6$
Answer- The correct answer is $6$.
Note:
Here you can also explain this question in the following way-
Since a and b are the two numbers whose product is $37$ so we can write-
$ \Rightarrow a \times b = 37$
On rearranging, we can write-
$ \Rightarrow a = \dfrac{{37}}{b}$
Now since we know that $37$ is a prime number so $b$ is equal to either $1$ or $37$ so on putting its value in the above equation, we get-
$ \Rightarrow $ If a$ = 1$ then b$ = 37$ or if $a = 37$ then b=$1$
Now, we can easily find the difference between the two numbers and solve the question further as we have done in the above solution.
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